In certain country, 43% of the population has type A blood. Suppose 21 people from that country are randomly chosen. Find the probability that: (Round all probabilities to four decimal places.) (a) exactly five people have type A blood. (b) strictly more than eighteen people have type A blood. (c) at most sixteen people have type A blood. (d) between five and eighteen (inclusive) people have type A blood. (e) Also find the mean number of people out of 21 who have type A blood, and the standard deviation to two decimal places. f= σ=
In certain country, 43% of the population has type A blood. Suppose 21 people from that country are randomly chosen. Find the probability that: (Round all probabilities to four decimal places.) (a) exactly five people have type A blood. (b) strictly more than eighteen people have type A blood. (c) at most sixteen people have type A blood. (d) between five and eighteen (inclusive) people have type A blood. (e) Also find the mean number of people out of 21 who have type A blood, and the standard deviation to two decimal places. f= σ=
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
![In a certain country, 43% of the population has type A blood. Suppose 21 people from that country are randomly chosen. Find the probability that (round all probabilities to four decimal places):
(a) Exactly five people have type A blood.
[Probability box]
(b) Strictly more than eighteen people have type A blood.
[Probability box]
(c) At most sixteen people have type A blood.
[Probability box]
(d) Between five and eighteen (inclusive) people have type A blood.
[Probability box]
(e) Also find the mean number of people out of 21 who have type A blood, and the standard deviation to two decimal places.
Mean (\(\mu\) = [Mean box])
Standard Deviation (\(\sigma\) = [Standard deviation box])](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b0cf1b8-84c6-4b32-890e-0885b2d3c430%2F75ca72ea-bf21-454d-8c7b-4aa3c8aaa5d0%2F3142rk9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In a certain country, 43% of the population has type A blood. Suppose 21 people from that country are randomly chosen. Find the probability that (round all probabilities to four decimal places):
(a) Exactly five people have type A blood.
[Probability box]
(b) Strictly more than eighteen people have type A blood.
[Probability box]
(c) At most sixteen people have type A blood.
[Probability box]
(d) Between five and eighteen (inclusive) people have type A blood.
[Probability box]
(e) Also find the mean number of people out of 21 who have type A blood, and the standard deviation to two decimal places.
Mean (\(\mu\) = [Mean box])
Standard Deviation (\(\sigma\) = [Standard deviation box])
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