In C programing(not C++ or C#), how can I complete my code for the expected output? Comments are from Teaching Assistant.Part 1Count the occurrences of a single character in a string. Example output:$ ./lab02 foobar o2$ ./lab02 foobarinvalid argumentsCount the occurrences of an N-character string in another string. Example output:$ ./lab02 abbabb bb2$ ./lab02 abbabb bc0You may use the C library function strstr() if you wish. char *strstr(char *a, char *b) returns a pointer to the first occurrence of b if b occurs in a, or NULL if b does not occur in a @vlab01 lab02-S$ gcc -g -o lab02 lab02.clab02.c: In function 'main':lab02.c:34:6: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]if (strlen(needle) == 1)) {lab02.c:34:6: warning: incompatible implicit declaration of built-in function 'strlen'lab02.c:34:6: note: include '' or provide a declaration of 'strlen'lab02.c:2:1:+#include int part1 (const char str[], int c)lab02.c:34:6:if (strlen(needle) == 1)) {lab02.c:34:26: error: expected statement before ')' tokenif (strlen(needle)1)) {==Alab02.c:38:17: error: 'str' undeclared (first use in this function)scanf("%s", str);lab02.c:38:17: note: each undeclared identifier is reported only once for each function it appears inlab02.c:39:17: error: 'ch' undeclared (first use in this function); did you mean 'char'?scanf("%s", ch);charlab02.c:41:12: warning: implicit declaration of function 'str_chnum' [-Wimplicit-function-declaration]printf(str_chnum(str, ch[0]));lab02.c:43:1: error: expected declaration or statement at end of input} 1 #include 2 int part1 (const char str[], int c)34int i;int count7for (i= 0; str[i] != '\0'; i++)8if (str[i]count++;10return (count);11 }1213 int part2 (const char str], int c){int i;141516int count = 0;17for (i = 0; str[i] != '\0'; i++)(str[i]count++;return (count);1819ifC)202122 }23char **argv)24 int main(int argc.25 {argv[1];// fooberargv[2];// o26272829//sudo code30//Create pointers to argv[1] and argv[2]3132//check if argv[2] is 1 characterchar *needleif (strlen(needle)argv[2];1)) {33343536//if its 1 character., call function part1()//if its more than 1 character, call function part2(37str);ch);38scanf("%s'39scanf("%s'40printf(str_chnum(str, ch[0]));return (0);414243 }

The C program to solve the problem is given in the below steps.

Answered: In C programing(not C++ or C#), how can…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Part 1

Count the occurrences of a single character in a string. Example output:

$ ./lab02 foobar o

$ ./lab02 foobar

invalid arguments

Count the occurrences of an N-character string in another string. Example output:

$ ./lab02 abbabb bb

$ ./lab02 abbabb bc

You may use the C library function strstr() if you wish. char *strstr(char *a, char *b) returns a pointer to the first occurrence of b if b occurs in a, or NULL if b does not occur in a

@vlab01 lab02-
S$ gcc -g -o lab02 lab02.c
lab02.c: In function 'main':
lab02.c:34:6: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
if (strlen(needle) == 1)) {
lab02.c:34:6: warning: incompatible implicit declaration of built-in function 'strlen'
lab02.c:34:6: note: include '<string.h>' or provide a declaration of 'strlen'
lab02.c:2:1:
+#include <string.h>
int part1 (const char str[], int c)
lab02.c:34:6:
if (strlen(needle) == 1)) {
lab02.c:34:26: error: expected statement before ')' token
if (strlen(needle)
1)) {
==
A
lab02.c:38:17: error: 'str' undeclared (first use in this function)
scanf("%s", str);
lab02.c:38:17: note: each undeclared identifier is reported only once for each function it appears in
lab02.c:39:17: error: 'ch' undeclared (first use in this function); did you mean 'char'?
scanf("%s", ch);
char
lab02.c:41:12: warning: implicit declaration of function 'str_chnum' [-Wimplicit-function-declaration]
printf(str_chnum(str, ch[0]));
lab02.c:43:1: error: expected declaration or statement at end of input
}

1 #include <stdio.h>
2 int part1 (const char str[], int c)
3
4
int i;
int count
7
for (i
= 0; str[i] != '\0'; i++)
8
if (str[i]
count++;
10
return (count);
11 }
12
13 int part2 (const char str], int c)
{
int i;
14
15
16
int count = 0;
17
for (i = 0; str[i] != '\0'; i++)
(str[i]
count++;
return (count);
18
19
if
C)
20
21
22 }
23
char **argv)
24 int main(int argc.
25 {
argv[1];// foober
argv[2];// o
26
27
28
29
//sudo code
30
//Create pointers to argv[1] and argv[2]
31
32
//check if argv[2] is 1 character
char *needle
if (strlen(needle)
argv[2];
1)) {
33
34
35
36
//if its 1 character., call function part1()
//if its more than 1 character, call function part2(
37
str);
ch);
38
scanf("%s'
39
scanf("%s'
40
printf(str_chnum(str, ch[0]));
return (0);
41
42
43 }

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