In ATUV, the measure ofV-90 the nmeashre of LUAand VT 88 feet. Find the length of UV to the nearest tenth of a foot. 139 8 Answer Submit Answer

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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**Problem Statement:**

In ΔTUV, the measure of ∠V = 90°, the measure of ∠U = 48°, and VT = 88 feet. Find the length of UV to the nearest tenth of a foot.

**Graph:**

A right triangle ΔTUV is depicted with the following details:
- ∠V is 90 degrees, making it a right angle.
- ∠U is 48 degrees.
- UV is marked as the side opposite to ∠U.
- VT is 88 feet, which is the side adjacent to ∠U.
- TU is the hypotenuse of the triangle.

To solve the problem and find the length of UV, we can use trigonometric functions. The tangent function is particularly useful here because it relates the opposite side to the adjacent side in a right triangle.

### Calculation:
\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \]

Where:
\[ \theta = 48^\circ \]
\[ \text{opposite} = UV \]
\[ \text{adjacent} = VT = 88 \]

Therefore,
\[ \tan(48^\circ) = \frac{UV}{88} \]
\[ UV = 88 \times \tan(48^\circ) \]

Using a calculator,
\[ \tan(48^\circ) \approx 1.1106 \]
So,
\[ UV \approx 88 \times 1.1106 \]
\[ UV \approx 97.8 \]

Thus, the length of UV to the nearest tenth of a foot is:
\[ \boxed{97.8 \text{ feet}} \]

Please enter your answer in the box provided and click "Submit Answer".
Transcribed Image Text:**Problem Statement:** In ΔTUV, the measure of ∠V = 90°, the measure of ∠U = 48°, and VT = 88 feet. Find the length of UV to the nearest tenth of a foot. **Graph:** A right triangle ΔTUV is depicted with the following details: - ∠V is 90 degrees, making it a right angle. - ∠U is 48 degrees. - UV is marked as the side opposite to ∠U. - VT is 88 feet, which is the side adjacent to ∠U. - TU is the hypotenuse of the triangle. To solve the problem and find the length of UV, we can use trigonometric functions. The tangent function is particularly useful here because it relates the opposite side to the adjacent side in a right triangle. ### Calculation: \[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \] Where: \[ \theta = 48^\circ \] \[ \text{opposite} = UV \] \[ \text{adjacent} = VT = 88 \] Therefore, \[ \tan(48^\circ) = \frac{UV}{88} \] \[ UV = 88 \times \tan(48^\circ) \] Using a calculator, \[ \tan(48^\circ) \approx 1.1106 \] So, \[ UV \approx 88 \times 1.1106 \] \[ UV \approx 97.8 \] Thus, the length of UV to the nearest tenth of a foot is: \[ \boxed{97.8 \text{ feet}} \] Please enter your answer in the box provided and click "Submit Answer".
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