In Assembly code: We have seen that multiplication by a power of two is easy with binary numerals: To multiply a number by 2^p corresponds to p left shifts. This works both for signed and unsigned numbers as long as we are careful with the range. Below is an attempt on a subroutine to multiply by a positive power of two. As noted in the contract, the assumption is that p is a strictly positive integer (i.e., 1, 2, 3 etc.). What happens when this subroutine is called with R5 = 3 and R6 = 11? Give a short but precise answer at the register level of the MCU
In Assembly code: We have seen that multiplication by a power of two is easy with binary numerals: To multiply a number by 2^p corresponds to p left shifts. This works both for signed and unsigned numbers as long as we are careful with the range. Below is an attempt on a subroutine to multiply by a positive power of two. As noted in the contract, the assumption is that p is a strictly positive integer (i.e., 1, 2, 3 etc.). What happens when this subroutine is called with R5 = 3 and R6 = 11? Give a short but precise answer at the register level of the MCU
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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In Assembly code: We have seen that multiplication by a power of two is easy with binary numerals: To
multiply a number by 2^p corresponds to p left shifts. This works both for signed and
unsigned numbers as long as we are careful with the range.
Below is an attempt on a subroutine to multiply by a positive power of two. As noted in
the contract, the assumption is that p is a strictly positive integer (i.e., 1, 2, 3 etc.).
multiply a number by 2^p corresponds to p left shifts. This works both for signed and
unsigned numbers as long as we are careful with the range.
Below is an attempt on a subroutine to multiply by a positive power of two. As noted in
the contract, the assumption is that p is a strictly positive integer (i.e., 1, 2, 3 etc.).
What happens when this subroutine is called with R5 = 3 and R6 = 11? Give a short
but precise answer at the register level of the MCU
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