In assembling a train from several railroad cars, two of the cars, with masses 2.0 x 10^4 kg and 4.0 x 10^4 kg, are rolled toward each other. When they meet, they couple and stick together. The lighter car has an initial speed of 1.5 m/s; the collision causes it to reverse direction at 0.25 m/s. What was the initial speed of the heavier car? * Before: m1 = 2.0 X 10 kg m2 = 4.0 X 104 %3D (Vix)i = 1.5 m/s (v2.)i %3D 1 2 After: m+ m2 (v)f =-0.25 m/s 1 2 Find: (v2x)i O -1.5 m/s O - 2 m/s -0.377 m/s O -1.125 m/s

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Chapter1: Units, Trigonometry. And Vectors
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the picture cut off but its 4.0 x 10^4 kg
1,
ミ
In assembling a train from several railroad cars, two of the cars, with
masses 2.0 x 10^4 kg and 4.0 x 10^4 kg, are rolled toward each other.
When they meet, they couple and stick together. The lighter car has an
initial speed of 1.5 m/s; the collision causes it to reverse direction at 0.25
m/s. What was the initial speed of the heavier car? *
Before:
m1 = 2.0 X 10ª kg
m2 = 4.0 X 104
(V)i = 1.5 m/s
(v2)i
After:
m1
+ m2
(vx)f =-0.25 m/s
Find: (v2x)i
-1.5 m/s
- 2 m/s
-0.377 m/s
-1.125 m/s
Transcribed Image Text:1, ミ In assembling a train from several railroad cars, two of the cars, with masses 2.0 x 10^4 kg and 4.0 x 10^4 kg, are rolled toward each other. When they meet, they couple and stick together. The lighter car has an initial speed of 1.5 m/s; the collision causes it to reverse direction at 0.25 m/s. What was the initial speed of the heavier car? * Before: m1 = 2.0 X 10ª kg m2 = 4.0 X 104 (V)i = 1.5 m/s (v2)i After: m1 + m2 (vx)f =-0.25 m/s Find: (v2x)i -1.5 m/s - 2 m/s -0.377 m/s -1.125 m/s
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