In ARST, RS = 2x + 10, ST = 3x - 2, and RT = x + 28. If ARST is 1 15. 2 equiangular, find ST. A. 2 B. 6 C. 12 D. 34 \2-2128 -26 -28 -6-5, 02 -> 2x+10=3x-2 10 - \y_2 +2 2 -24

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