In aqueous solution d-glucose (or dextrose) exists in equilibrium between a linear and cyclic form shown below. A. Mark all the stereocenters in the linear form of the molecule. Number them 1,2,3, etc. B. Draw out the reaction that converts the linear form to the 6-membered ring using the arrow formalism. C. Identify the stereocenters in the 6-member ring that correspond to the stereocenters in the linear form marking them as 1,2,3, etc. The reaction also created a new stereocenter. Mark it as H- HOH Ho H-OH o--H H--OH H-OH HO H он HO,

In aqueous solution d-glucose (or dextrose) exists in equilibrium between a linear and cyclic form shown below. A. Mark all the stereocenters in the linear form of the molecule. Number them 1,2,3, etc. B. Draw out the reaction that converts the linear form to the 6-membered ring using the arrow formalism. C. Identify the stereocenters in the 6-member ring that correspond to the stereocenters in the linear form marking them as 1,2,3, etc. The reaction also created a new stereocenter. Mark it as H- HOH Ho H-OH o--H H--OH H-OH HO H он HO,

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Glucose is a simple sugar with five substituents bonded to a sixmembered ring.a.Using a chair representation, draw the most stable arrangement of these substituents on the six-membered ring. b.Convert this representation to one that uses a hexagon with wedges and dashed wedges. c.Draw a constitutional isomer of glucose. d.Draw a stereoisomer that has an axial OH group on one carbon.
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1,2-ditert-butylcyclohexane is an interesting case of a conformational study. The cis isomer is more stable than the trans isomer, although the trans isomer presents a conformer with both substituents in equatorial positions. In order to analyze this fact:a. Draw the conformational equilibrium of both compounds. Explain using and drawing the structures why this difference happens (the one described above). b. In the trans isomer, the di-axial conformation is 25.9 kJ / mol more stable than the di-equatorial. Calculate the energy of the di-equatorial conformation.
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