In an isosceles right triangle ABC, with the right angle at C, the length of a leg is 20 inches. Perpendiculars are dropped from C to the hypotenuse, from the foot of this perpendicular to leg CB, from the foot if this perpendicular to AB then back to leg CB, etc without end. Find the sum of the lengths of all perpendiculars.

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A: topic - lowest common multiple 56=2*2*2*7 24=2*2*2*3 LCM(56,24)=2*2*2*3*7=168

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A: The given triangles have,RS=8, RU=24, RT=4x-4, TV=4x+5

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A: From the given figure; AC¯=5 OB¯= OC= radius=3 Now find the length of OA OA=AC+OCOA=5+3OA=8

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A: To arrange the sides of given triangle in increasing order.

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