In an infinitely repeated Prisoner's Dilemma, a version of what is known as a "tit for tat" strategy of a player iis described as follows: There are two "statuses" that player i might be in during any period: "normal" and "revenge"; . In a normal status player i cooperates; In a revenge status player i defects; From a normal status, player i switches to the revenge status in the next period only if the other player defects in this period; . From a revenge status player i automatically switches back to the normal status in the next period regardless of the other player's action in this period.
In an infinitely repeated Prisoner's Dilemma, a version of what is known as a "tit for tat" strategy of a player iis described as follows: There are two "statuses" that player i might be in during any period: "normal" and "revenge"; . In a normal status player i cooperates; In a revenge status player i defects; From a normal status, player i switches to the revenge status in the next period only if the other player defects in this period; . From a revenge status player i automatically switches back to the normal status in the next period regardless of the other player's action in this period.
Managerial Economics: Applications, Strategies and Tactics (MindTap Course List)
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Chapter13: best-practice Tactics: Game Theory
Section: Chapter Questions
Problem 2E
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![8. In an infinitely repeated Prisoner's Dilemma, a version of what is known as a "tit for tat" strategy of a player i is described as follows:
There are two "statuses" that player i might be in during any period: "normal" and "revenge";
.
In a normal status player i cooperates;
.
In a revenge status player i defects;
From a normal status, player i switches to the revenge status in the next period only if the other player defects in this period;
From a revenge status player i automatically switches back to the normal status in the next period regardless of the other player's action in this
period.
Consider an infinitely repeated game so that with probability p that the game continues to the next period and with probability (1-p) it ends.
Defect (D)
Cooperate (C)
4,4
0,5
Cooperate (C)
Defect (D)
5,0
1,1
What is the payoff for player 2 from always cooperating when player 1 uses this tit for tat strategy and begins in a normal status? How about always
defecting when 1 begins in a normal status?
O a) 4 + 4p + 4p² +. 4p³ + ...;
b) 4 + 4p + 4p² + 4p³ +...;
O c) 5+ 4p + 4p² + 4p³ + ...;
O d) 5+ 4p + 4p² + 4p³ + ...;
5+p+p²+p³ +...
5+p+5p²+p³ +...
4 + 4p + 4p² + 4p³ + ...
5+p+p² +p³ +...](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F13465df6-03b7-41c9-b175-ca7401eeda0b%2Fb9a187ff-5bc6-4aef-a5bd-65d73eb0fcbf%2Fu3th00g_processed.png&w=3840&q=75)
Transcribed Image Text:8. In an infinitely repeated Prisoner's Dilemma, a version of what is known as a "tit for tat" strategy of a player i is described as follows:
There are two "statuses" that player i might be in during any period: "normal" and "revenge";
.
In a normal status player i cooperates;
.
In a revenge status player i defects;
From a normal status, player i switches to the revenge status in the next period only if the other player defects in this period;
From a revenge status player i automatically switches back to the normal status in the next period regardless of the other player's action in this
period.
Consider an infinitely repeated game so that with probability p that the game continues to the next period and with probability (1-p) it ends.
Defect (D)
Cooperate (C)
4,4
0,5
Cooperate (C)
Defect (D)
5,0
1,1
What is the payoff for player 2 from always cooperating when player 1 uses this tit for tat strategy and begins in a normal status? How about always
defecting when 1 begins in a normal status?
O a) 4 + 4p + 4p² +. 4p³ + ...;
b) 4 + 4p + 4p² + 4p³ +...;
O c) 5+ 4p + 4p² + 4p³ + ...;
O d) 5+ 4p + 4p² + 4p³ + ...;
5+p+p²+p³ +...
5+p+5p²+p³ +...
4 + 4p + 4p² + 4p³ + ...
5+p+p² +p³ +...
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