In an ideal calorimeter, 250.0 mL of water at 50.O °C and 150.0 mL of water at 20.0 °C are mixed, producing a final temperature of 35.0 °C. The qwater formula below can be used to determine the amount of heat absorbed or released by either water mass. J Jwater = mwater X 4.184 g.ºC x Δνater What value would you enter for mwater, to calculate the amount of heat absorbed by the cooler water mass? O 250.0 grams O 100.0 grams O 400.0 grams 150.0 grams

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In an ideal calorimeter,
250.0 mL of water at 50.0 °C
and 150.0 mL of water at 20.0 °C are mixed,
producing a final temperature of 35.0 °C.
The qwater formula below can be used to determine the amount of heat absorbed or released by
either water mass.
× ATvater
J
84
g.°C
qwater
mwater X
What value would you enter for mwater, to calculate the amount of heat absorbed by the cooler
water mass?
250.0 grams
100.0 grams
400.0 grams
150.0 grams
Transcribed Image Text:In an ideal calorimeter, 250.0 mL of water at 50.0 °C and 150.0 mL of water at 20.0 °C are mixed, producing a final temperature of 35.0 °C. The qwater formula below can be used to determine the amount of heat absorbed or released by either water mass. × ATvater J 84 g.°C qwater mwater X What value would you enter for mwater, to calculate the amount of heat absorbed by the cooler water mass? 250.0 grams 100.0 grams 400.0 grams 150.0 grams
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