In an experiment to measure a for a certain gas, it was found that the steady current is 3.8x10 A at a voltage of 8 kV and at a distance of 4 mm between the plane electrodes. Keeping the field constant and reducing the distance to 1 mm resulted in a current of 3.8x10 A.
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Q: Millikan measured the electron's charge by observing tiny charged oil drops in an electric field.…
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A: Given, Electric field , E = 50 V/m Charge, Q = 10-6 C F = ?
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A: F1=kq1q2r12F2=kq1q2r22F2F1=kq1q2r22kq1q2r12F2=r1r22F1
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A: Given Data: Charge, Standard Data:
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A: Given data: Weight of oil drop = mg = 5.43 x 10^-14 N Electric field = E = 3.77 x 10^4 N/C
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A: The weight of an oil drop is 3.34x10-14 N.The strength of the electric field is 2.98x104 N/C.
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