In an experiment it was found that the total charge on an oil drop was 5.93 3 10218 C. How many negative charges does the drop contain? How was the charge of one negative election found?

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  1. In an experiment it was found that the total charge on an oil drop was 5.93 3 10218 C. How many negative charges does the drop contain?
    How was the charge of one negative election found?

 

### Calculation of the Number of Negative Charges on an Oil Drop

**Given:**

Total charge on an oil drop, \( Q = 5.93 \times 10^{-18} \) C

**Formula:**

The number of negative charges on the oil drop is calculated using the formula:

\[ n = \frac{Q}{e} \]

where:

- \( n \) is the number of negative charges.
- \( e \) is the charge of one negative electron.

**Charge of One Negative Electron:**

\[ e = 1.6 \times 10^{-19} \) C

**Calculation:**

Substitute the values of \( Q \) and \( e \) into the equation:

\[ n = \frac{5.93 \times 10^{-18} \text{ C}}{1.6 \times 10^{-19} \text{ C}} \]

\[ n = 37 \]
Transcribed Image Text:### Calculation of the Number of Negative Charges on an Oil Drop **Given:** Total charge on an oil drop, \( Q = 5.93 \times 10^{-18} \) C **Formula:** The number of negative charges on the oil drop is calculated using the formula: \[ n = \frac{Q}{e} \] where: - \( n \) is the number of negative charges. - \( e \) is the charge of one negative electron. **Charge of One Negative Electron:** \[ e = 1.6 \times 10^{-19} \) C **Calculation:** Substitute the values of \( Q \) and \( e \) into the equation: \[ n = \frac{5.93 \times 10^{-18} \text{ C}}{1.6 \times 10^{-19} \text{ C}} \] \[ n = 37 \]
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