In an experiment, exactly 1.60 grams of salicylic acid (138.121 g/mol) reacted with excess methanol to produce methyl salicylate (152.1494 g/mol). Suppose the actual yield is 1.66 grams methyl salicylate, what is the % yield yield? C,H6O3 + CH3OH Cg Hg O3 + H2O 94% 49% 74% 100%

In an experiment, exactly 1.60 grams of salicylic acid (138.121 g/mol) reacted with excess methanol to produce methyl salicylate (152.1494 g/mol). Suppose the actual yield is 1.66 grams methyl salicylate, what is the % yield yield? C,H6O3 + CH3OH Cg Hg O3 + H2O 94% 49% 74% 100%

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

In an experiment, exactly 1.60 grams of salicylic acid (138.121 g/mol) reacted with excess methanol to
produce methyl salicylate (152.1494 g/mol). Suppose the actual yield is 1.66 grams methyl salicylate,
what is the % yield yield?
C,H6O3 + CH3OH
→ C3 Hg O3 + H2O
94%
49%
O 74%
O 100%
O O

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