In an elastic head-on collision, a 0.60 kg cart moving at 5.0 m/s [W] collides with a 0.80 kg cart moving at 2.0 m/s [E]. The collision is cushioned by a spring (k = 1200 N/m). a) Determine the velocity of each cart after the collision. b) Determine the maximum compression of the spring.
In an elastic head-on collision, a 0.60 kg cart moving at 5.0 m/s [W] collides with a 0.80 kg cart moving at 2.0 m/s [E]. The collision is cushioned by a spring (k = 1200 N/m). a) Determine the velocity of each cart after the collision. b) Determine the maximum compression of the spring.
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In an elastic head-on collision, a 0.60 kg cart moving at 5.0 m/s [W] collides with a 0.80 kg cart moving at 2.0 m/s [E]. The collision is cushioned by a spring (k = 1200 N/m).
a) Determine the velocity of each cart after the collision.
b) Determine the maximum compression of the spring.
I asked this question before and only one velocity was given, however I need a velocity for each cart. I also noticed that the person answering before didn't adjust the cart to the Earth's frame of reference. I attached my answer for part a) but if someone could explain how to do this and if mine is right. Thank you.
![4. i) m, = 0.80kg
m2 = 0.60kg
V11 = 2.0m/s [E]
V2i = 5.0m/s [W]
Vis = ?
Vas = ?
Vii= 2.0m/s [E]
Vzi= 5.0m/s [W]
Vii= 7.0m/s [E]
Vzi = Om/s
Let East be the positive direction
V(m,- m,)
Vif =
(m,+ m,)
7.0m/s (0.80kg - 0.60kg)
(0.60kg + 0.80kg)
1.4kg-mis
1.4kg
= 1m/s [E]
= 1m/s + (- 5.0m/s)
- 4m/s [E]
4m/s [W]
(2m, v
V2f- (m,+m,)
(2)(0.80kgN7.0m/s)
(0.60kg + 0.80kg)
11.2kg-m/s
1.4kg
8m/s [E]
8m/s + (- 4.0m/s)
4m/s [E]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff3bafd07-3e94-45bd-9b4a-f639f53c39ab%2F224683d9-0062-41e2-b456-0830f7bcb2c9%2Fj63ud3h_processed.png&w=3840&q=75)
Transcribed Image Text:4. i) m, = 0.80kg
m2 = 0.60kg
V11 = 2.0m/s [E]
V2i = 5.0m/s [W]
Vis = ?
Vas = ?
Vii= 2.0m/s [E]
Vzi= 5.0m/s [W]
Vii= 7.0m/s [E]
Vzi = Om/s
Let East be the positive direction
V(m,- m,)
Vif =
(m,+ m,)
7.0m/s (0.80kg - 0.60kg)
(0.60kg + 0.80kg)
1.4kg-mis
1.4kg
= 1m/s [E]
= 1m/s + (- 5.0m/s)
- 4m/s [E]
4m/s [W]
(2m, v
V2f- (m,+m,)
(2)(0.80kgN7.0m/s)
(0.60kg + 0.80kg)
11.2kg-m/s
1.4kg
8m/s [E]
8m/s + (- 4.0m/s)
4m/s [E]
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