In an effort to estimate the mean amount spent per customer for dinner at a major Atlanta restaurant, data were collected from 64 randomly selected customers.  The sample mean was calculated as $27.75 with a sample standard deviation of $4.  We wish to develop a 91% confidence interval for the mean amount spent per customer for dinner at this restaurant.  Assume that the standard deviation of the amounts spent by ALL customers is $4.30. What is the variable of interest? A) amount spent at restaurant  B) their age

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A: 7)Given data is11.5, 21.9, 12.7, 9.0, 19.2, 18.5, 19.3, 1.9, 19.2, 0.8, 28.8, 17.7

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A: From the provided information, n1=47x1=48.2σ1=4.1n2=39x2=46.5σ2=2.5α=0.10

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A: I hope this helped you and you learned a lot :) If you have any questions or clarification, do not…

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