In an aqueous solution of a certain acid the acid is 0.083% dissociated and the pH is 4.20. Calculate the acid dissociation constant K, of the acid. Round your answer to 2 significant digits. K = 0 0 10

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Chapter1: Chemical Foundations
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**Question:**

In an aqueous solution of a certain acid, the acid is 0.083% dissociated and the pH is 4.20. Calculate the acid dissociation constant \( K_a \) of the acid. Round your answer to 2 significant digits.

**Answer Box:**

\[ K_a = \quad \text{(textbox where the answer is to be entered)} \]

**Additional Tools:**

- Check box labeled with \( \times 10 \)
- Three option buttons labeled with an "X" (to cancel), a "↻" symbol (likely to reset), and a "?" (for help).

**Explanation:**

To solve this, use the following steps:

1. **Calculate the concentration of \( \text{H}^+ \) ions:**
   \[
   \text{pH} = -\log[\text{H}^+]
   \]
   Rearrange the equation to find \( [\text{H}^+] \):
   \[
   [\text{H}^+] = 10^{-\text{pH}} = 10^{-4.20}
   \]

2. **Determine the degree of dissociation (\( \alpha \)):**
   \[
   \alpha = \frac{0.083}{100} = 0.00083
   \]

3. **Relate the degree of dissociation to the initial concentration \( C_0 \):**
   \[
   [\text{H}^+] = \alpha \cdot C_0
   \]
   Thus, \( C_0 \):
   \[
   C_0 = \frac{[\text{H}^+]}{\alpha}
   \]

4. **Substitute all known values:**
   \[
   K_a = \alpha \cdot C_0^2
   \]

5. **Round the final answer to 2 significant digits.**
Transcribed Image Text:**Question:** In an aqueous solution of a certain acid, the acid is 0.083% dissociated and the pH is 4.20. Calculate the acid dissociation constant \( K_a \) of the acid. Round your answer to 2 significant digits. **Answer Box:** \[ K_a = \quad \text{(textbox where the answer is to be entered)} \] **Additional Tools:** - Check box labeled with \( \times 10 \) - Three option buttons labeled with an "X" (to cancel), a "↻" symbol (likely to reset), and a "?" (for help). **Explanation:** To solve this, use the following steps: 1. **Calculate the concentration of \( \text{H}^+ \) ions:** \[ \text{pH} = -\log[\text{H}^+] \] Rearrange the equation to find \( [\text{H}^+] \): \[ [\text{H}^+] = 10^{-\text{pH}} = 10^{-4.20} \] 2. **Determine the degree of dissociation (\( \alpha \)):** \[ \alpha = \frac{0.083}{100} = 0.00083 \] 3. **Relate the degree of dissociation to the initial concentration \( C_0 \):** \[ [\text{H}^+] = \alpha \cdot C_0 \] Thus, \( C_0 \): \[ C_0 = \frac{[\text{H}^+]}{\alpha} \] 4. **Substitute all known values:** \[ K_a = \alpha \cdot C_0^2 \] 5. **Round the final answer to 2 significant digits.**
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