In an aqueous solution of a certain acid the acid is 0.083% dissociated and the pH is 4.20. Calculate the acid dissociation constant K, of the acid. Round your answer to 2 significant digits. K = 0 0 10
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![**Question:**
In an aqueous solution of a certain acid, the acid is 0.083% dissociated and the pH is 4.20. Calculate the acid dissociation constant \( K_a \) of the acid. Round your answer to 2 significant digits.
**Answer Box:**
\[ K_a = \quad \text{(textbox where the answer is to be entered)} \]
**Additional Tools:**
- Check box labeled with \( \times 10 \)
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**Explanation:**
To solve this, use the following steps:
1. **Calculate the concentration of \( \text{H}^+ \) ions:**
\[
\text{pH} = -\log[\text{H}^+]
\]
Rearrange the equation to find \( [\text{H}^+] \):
\[
[\text{H}^+] = 10^{-\text{pH}} = 10^{-4.20}
\]
2. **Determine the degree of dissociation (\( \alpha \)):**
\[
\alpha = \frac{0.083}{100} = 0.00083
\]
3. **Relate the degree of dissociation to the initial concentration \( C_0 \):**
\[
[\text{H}^+] = \alpha \cdot C_0
\]
Thus, \( C_0 \):
\[
C_0 = \frac{[\text{H}^+]}{\alpha}
\]
4. **Substitute all known values:**
\[
K_a = \alpha \cdot C_0^2
\]
5. **Round the final answer to 2 significant digits.**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c542873-90da-4d8f-af03-4e4a6198699f%2Fc6f8628f-1963-4d53-ac2e-b579180a4038%2Fewrupgn_processed.jpeg&w=3840&q=75)
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