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In an anthropological research, subjects were tested for a gene that has been found to increase the risk for a disease. The probability that a person carries the gene is 0.1. What is the probability that five or more people need to be tested to detect two with the gene? a. None among the choices Ob. NEGBINOM.DIST(2,2,0.1, TRUE) = 0.0523 O. 1- P(X<=4) = 1- NEGBINOM.DIST(2,2,0.1, TRUE) = 0.9477 O d.1- P(X<=3) = 1 - NEGBINOM.DIST(1,2,0.1, TRUE) = 0.972

In an anthropological research, subjects were tested for a gene that has been found to increase the risk for a disease. The probability that a person carries the gene is 0.1. What is the probability that five or more people need to be tested to detect two with the gene? a. None among the choices Ob. NEGBINOM.DIST(2,2,0.1, TRUE) = 0.0523 O. 1- P(X<=4) = 1- NEGBINOM.DIST(2,2,0.1, TRUE) = 0.9477 O d.1- P(X<=3) = 1 - NEGBINOM.DIST(1,2,0.1, TRUE) = 0.972

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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In an anthropological research, subjects were tested for a gene that has been found to increase the risk for a disease. The probability that a person carries the gene is 0.1. What is the probability that five or more people need to be tested to detect two with the gene? a. None among the choices O b. NEGBINOM.DIST(2,2,0.1, TRUE) = 0.0523 %3D O. 1- P(X<=4) = 1- NEGBINOM.DIST(2,2,0.1, TRUE) = 0.9477 O d. 1- P(X<=3) = 1- NEGBINOM.DIST(1,2,0.1, TRUE) = 0.972
Transcribed Image Text:In an anthropological research, subjects were tested for a gene that has been found to increase the risk for a disease. The probability that a person carries the gene is 0.1. What is the probability that five or more people need to be tested to detect two with the gene? a. None among the choices O b. NEGBINOM.DIST(2,2,0.1, TRUE) = 0.0523 %3D O. 1- P(X<=4) = 1- NEGBINOM.DIST(2,2,0.1, TRUE) = 0.9477 O d. 1- P(X<=3) = 1- NEGBINOM.DIST(1,2,0.1, TRUE) = 0.972
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