In an air pollution analysis, 3 L of polluted air is passed through 50 mL of 0,0116 M Ba (OH) 2 solution and the carbon dioxide (CO2) in it is precipitated as BaCO3. The excess of the base is titrated with 23.6 mL 0.0108 M HCl in addition to the phenol phthalate (f.f.) indicator. Calculate the CO2 concentration in this air sample in ppm. (Take the density of CO2 as 1.98 g / L. C = 12, O = 16 g / mol).
In an air pollution analysis, 3 L of polluted air is passed through 50 mL of 0,0116 M Ba (OH) 2 solution and the carbon dioxide (CO2) in it is precipitated as BaCO3. The excess of the base is titrated with 23.6 mL 0.0108 M HCl in addition to the phenol phthalate (f.f.) indicator. Calculate the CO2 concentration in this air sample in ppm. (Take the density of CO2 as 1.98 g / L. C = 12, O = 16 g / mol).
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In an air pollution analysis, 3 L of polluted air is passed through 50 mL of 0,0116 M Ba (OH) 2 solution and the carbon dioxide (CO2) in it is precipitated as BaCO3. The excess of the base is titrated with 23.6 mL 0.0108 M HCl in addition to the phenol phthalate (f.f.) indicator. Calculate the CO2 concentration in this air sample in ppm. (Take the density of CO2 as 1.98 g / L. C = 12, O = 16 g / mol).
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