In a test of the quality of two television commercials, each commercial was shown in a separate test area six times over a one-week period. The following week a telephone survey was conducted to identify individuals who had seen the commercials. Those individuals were asked to state the primary message in the commercials. The following results were recorded. Commercial A Commercial B Number Who Saw Commercial 150 200 Number Who Recalled Message 63 60 Use a = .05 and test the hypothesis that there is no difference in the recall proportions for the two commercials. Formulate the null and the alternative hypotheses. Но : рі — р2 | еqual to 0 На : Рі — р2 not equal to 0 What is the value of the test statistic (to 2 decimals)? 2.33 What is the p-value (to 4 decimals)? 0.0198

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Q: Given the following: P(A) = 0.22, P(B) = 0.46, with A and B independent. Find: P(A or B) 0.5788…

A: P(A)=0.22P(B)=0.46A and B are independent soP(A and B)=P(A)*P(B)

Q: What is the accuracy of 0.8

A: givenaccuracy is 0.8we find in percentage

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Q: P(0.68<:<2.18):

A: Z~N(0,1) To find:

Q: • Play 45 cm 22 cm 30 cm 25 cm 153

A: We have to find correct perimeter.

Q: what is the precision of 0.008?

A: The given number is .The aim is to find the precision of the number.

Q: the sensitivity

A: 93(a=7), 92(a=8) It seems that it's not coherent  Or not coherent formula

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A:

Q: How do you find the P-value using ti-84 calculator? df=7 , M&gt;98.6 , n=8 , t=2.428

A: It is given that the t value 2.428 and df is 7.

Q: Where does the 0.025 come from?

A: The given confidence level is 95%.

Q: Can you round the answers to third decimal? For example, 0.46

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Q: Given P(B) = 0.28, P(A and B) = 0.29, P(A or B) = 0.45, what is P(A)? Answer in decimal form.…

A: Given :  P(B) = 0.28 P(A and B) = 0.29 P(A or B) = 0.45

Q: So what is the answer rounded to three decimal place

A: The hypothesized mean is 2.85.

Q: t says the answer is 0.8597 I'm not sure how they got that

A: The mean is 97.7 and the standard deviation is 0.6.

Q: How do we calculate p?

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Q: NAME: AGE: DATE: Copyright 2012 www.fun-free-party-games.com

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A: Evaluate: 13−108+613−108+6 .

Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.