In a test of H0: μ = 16.7 against HA: μ > 16.7, the sample data with sample size 50 yielded a test statistic z = 1.42. Find the p-value for the test. Group of answer choices 0.5778 0.4222 0.0778 0.9222
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- A dietitian wishes to see if a person's cholesterol level will change if the diet is supplemented by a certain mineral. Seven subjects were pretested and then took the mineral supplement for a six-week period. The results are shown below in the table. Use a paired samples t-chart at a = 0.01 significance level to see difference (Before - After) between the cholesterol levels. State the hypotheses and conclusion. Also, conduct a 99% confidence interval. Subject 1 Before 210 After 190 2 205 170 3 208 210 4 192 188 5 178 173 6 244 228 7 211 198In an experiment, two different species of flowers were crossbred. The resulting 217 flowers from this crossbreeding experiment were categorized by the color of the flower and the stigma. The table provides the study results. 1: Magenta flower with Green stigma 2: Magenta flower with Red stigma 3: Red flower 4: Red flower Flower Type with Green stigma with Red stigma Observed # Flowers 115 49 32 21 According to genetic theory, the four resulting flower types should follow the ratio of 9:3:3:1, that is, should follow the following population proportions of 0.5625, 0.1875, 0.1875, and 0.0625. The biologist is interested in assessing whether the distribution for flower type for the experiment matches these genetic theory rates. The hypotheses to be tested are Họ: P1 = 0.5625, p2 = 0.1875, P3 = 0.1875, p4 = 0.0625, where p; represents the proportion of flowers in the population in group i HA: at least one p; differs from the stated proportionsSamples were collected from two ponds in the Bahamas to compare salinity values (in parts per thousand). Several samples were drawn at each site. Pond 1: 37.03, 37.45, 36.75, 37.54, 37.71, 37.02, 37.32 Pond 2: 38.89, 39.05, 38.51, 38.53, 38.71 Use a 2% significance level to test the claim that the two ponds have the same mean salinity value. Assume that nothing is known about the population distribution of salinities. (a) Enter the rank values in the same order as in the original sample. The rank values for Pond 1 are: The rank values for Pond 2 are: (b) The test statistic is: . (c) The test critical value is: . (d) The conclusion isA. There is not sufficient evidence to indicate that the two ponds have different distributions of salinity values.B. There is sufficient evidence to indicate that the two ponds have different distributions of salinity values.
- Find the best point estimate for the ratio of the population variances given the following sample statistics. Round your answer to four decimal places. n1=18n1=18, n2=28n2=28, s12=75.455s12=75.455, s22=55.482s22=55.482 Copy DataThe total size of a university is 7,610. Determine the sample size for a study using the COchran's formula provided that Z = 1.96 and e = 0.05The local labor market for the XYZ Company is 75% white. The HR Manager for the XYZ Company wants to see whether her company is significantly more or less white than the local labor market. What statistical test should she use to analyze the data? a. Factorial ANOVA b. Chi Square Goodness of Fit Test c. Repeated Measures ANOVA d. Independent Samples t-test e. One sample t-test
- You want to compare differences in prior arrests across ethnicity in your study, you measured ethnicity as white =0 black =1 hispanic=2, and other =3. Prior arrests was recorded as the number of prior arrests. which test would you perform to see if arrests differ across diffrent ethnic categories? A. ANOVA B. T-testAlpha equals 0.01 level of significance for the given sample data.A sample of 100 clients of an exercise facility was selected. Let X = the number of days per week that a randomly selected client uses the exercise facility. Frequency 2 1 15 30 3 27 4 10 8 6. 8 Find the 80th percentile.
- Q7: what is the answer for both parts to this question, answer choices are provided in the picturesa survey is conducted to compare the proportions of men and women whoaccess their bank statements online. Denoting the population propotions by Pm and Pw, a two-proportion z-test is carried out to test Ho: pm = pw against Ha: pm > pw. The values of the test statistic is found to be z = 0.784, and the p-value for the test is found to be 0.216. Which of the following is the correct interpretation of the p-value? a) given that ha is true, the probability of getting a value of z at least as large as 0.784 is 0.216. b) given the results of the survey, the probability that Pm > Pw is 0.216. c) given the results of the survey, the probability that Pm = Pw is 0.216. d) none of the above
