In a survey of 2847 adults, 1405 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is

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I was able to find q=0.578, but i dont know how to locate the left and right endpoint. 

**Survey Analysis and Confidence Interval Construction**

In a survey conducted with 2,847 adults, 1,405 respondents reported that they have started paying bills online in the last year.

**Objective:**
Construct a 99% confidence interval for the population proportion and interpret the results.

**Process:**
To achieve this, follow the standard procedure for constructing confidence intervals for a population proportion. 

**Result Interpretation:**
A 99% confidence interval for the population proportion is denoted as \((\_\_\_, \_\_\_)\).
(Round to three decimal places as needed.)

This interval will provide a range in which we are 99% confident that the true population proportion lies within. Calculations should include determining the sample proportion, standard error, and using the critical value for a 99% confidence level.
Transcribed Image Text:**Survey Analysis and Confidence Interval Construction** In a survey conducted with 2,847 adults, 1,405 respondents reported that they have started paying bills online in the last year. **Objective:** Construct a 99% confidence interval for the population proportion and interpret the results. **Process:** To achieve this, follow the standard procedure for constructing confidence intervals for a population proportion. **Result Interpretation:** A 99% confidence interval for the population proportion is denoted as \((\_\_\_, \_\_\_)\). (Round to three decimal places as needed.) This interval will provide a range in which we are 99% confident that the true population proportion lies within. Calculations should include determining the sample proportion, standard error, and using the critical value for a 99% confidence level.
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