### Constructing a 99% Confidence Interval for Population Proportion#### Problem StatementIn a survey of 2583 adults, 1482 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion and interpret the results.#### SolutionA 99% confidence interval for the population proportion is \( ( \blacksquare , \blacksquare ) \) (Round to three decimal places as needed).#### Interpretation of ResultsChoose the correct answer below:- **A.** With 99% confidence, it can be said that the sample proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval.- **B.** The endpoints of the given confidence interval show that adults pay bills online 99% of the time.- **C.** With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval.#### Explanation:To construct the confidence interval, we use the formula for the confidence interval for a population proportion \( p \):\[CI = \hat{p} \pm Z_{\alpha/2} \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}\]Where:- \(\hat{p}\) is the sample proportion, \( \hat{p} = \frac{1482}{2583} \)- \( Z_{\alpha/2} \) is the critical value from the standard normal distribution for a 99% confidence level.- \( n \) is the sample size, \( n = 2583 \)Calculate \(\hat{p}\) and use the Z-value for 99% confidence level (approximately 2.576) to find the confidence interval.Select the correct interpretation based on the constructed interval.

Confidence interval is an interval such that the probability of the unknown parameter to be included…

In a survey of 2583 adults, 1482 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is ( ). (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. O A. With 99% confidence, it can be said that the sample proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval. O B. ,The endpoints of the given confidence interval show that adults pay bills online 99% of the time. OC. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval.

In a survey of 2583 adults, 1482 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is ( ). (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. O A. With 99% confidence, it can be said that the sample proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval. O B. ,The endpoints of the given confidence interval show that adults pay bills online 99% of the time. OC. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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