In a survey of 2569 adults in a recent​ year, 1303 say they have made a New​ Year's resolution. Construct​ 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals.

Q: In a survey of 2224 adults in a recent​ year, 1280 say they have made a New​ Year's resolution.…

A: Obtain the 90% confidence interval for the population proportion. The 90% confidence interval for…

Q: describe how you would construct a 90% confidence interval to estimate the population mean age for…

A: Here, we need to discuss the steps involved in constructing the 90% confidence interval to estimate…

Q: adults in a recent​ year, 742 made a New​ Year's resolution to eat healthier.   Construct​ 90% and​…

A: The value of z at a 90% confidence level is 1.645, which can be found by using the standard normal…

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Sample proportion=p^=21380z=critical value for 95% confidence interval=1.96n=sample size=380

Q: In a survey of 2313 adults, 714 say they believe in UFOs.   Construct a 90% confidence interval for…

A: Given, In a survey of 2313 adults, 714 say they believe in UFOs. n=2313 x=714 Sample proportion:…

Q: n a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A:

Q: If n=590 and p=0.93, construct a 90% confidence interval.

A: Express the expression for the confidence interval. C.I=p±Z*p(1-p)n Here, Z* is the critical value .…

Q: In a survey of 4061 ​adults, 738 say they have seen a ghost. Construct a​ 99% confidence interval…

A: In this question, it has been given that 738 people out of 4061 people have seen the ghost, we have…

Q: when 282 college students are randomly selected and surveyed, it is found that 109 own a car. find a…

A: It is given that sample size (n) is 282 and x is 109.

Q: a survey of 3409 adults, 1445 say they have started paying bills online in the last year.  Construct…

A: The confidence interval = 99%The faovarble cases [x] = 1445The sample size [n] = 3409

Q: A doctor would like to estimate the mean difference in the number of hours of sleep for seniors in…

A: Random sample of 50 high school seniors  Random sample of 50 seniors from the colleges in his county…

Q: In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last…

Q: In a survey of 3292 adults, 1470 say they have started paying bills online in the last year.…

A: Using Excel formula “=NORM.S.INV(1-(0.01/2))”, the critical value for 99% confidence level is…

Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

A:

Q: 9. A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence…

A: In a survey of 280 homeless persons showed that 63 were veterans.

Q: In a random sample of 600 adults, 270 described themselves as vegetarians. Construct a 99%…

A: In a random sample of 600 adults, 270 described themselves as vegetarians.

Q: In a survey of 3342 adults, 1489 say they have started paying bills online in the last year.…

A: Given Information: To construct a 99% confidence interval for the population proportion and…

Q: A survey showed 980 of 1500 adult respondents believe in global warming. Construct a 95% confidence…

A:

Q: n a survey of 3196 adults, 1405 say they have started paying bills online in the last year.…

A: Given data, n=3196 x=1405 p=x/n=1405/3196 =0.4396 z-value at 99% confidence is Zc=2.576

Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: In a random sample of 230 men , 18 or older , 142 were married. Construct and explain a 90%…

A: Solution: Let X be the number of married men 18 or older and n be the sample number of men. From the…

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

A:

Q: Out of 42738 freshmen entering the State University system,  27298 of them need to take remedial…

A:

Q: In a survey of 2291 ​adults, 708 say they believe in UFOs.   Construct a 90% confidence interval for…

A:

Q: In a random sample of 230 men, 18 or older, 142 are married. Construct and explain a 98% confidence…

A: Given Data Sample Size, n = 230 Number of successes, x = 142.0 Significance level,…

Q: A research institute poor ass respondents if they felt vulnerable to identity theft. In the pool, N…

A:

Q: In a survey of 2130 adults in a recent​ year, 1491 say they have made a New​ Year's resolution.…

A: Solution: Let X be the number of adults say they have made a New year’s resolution and n be the…

Q: When 370 junior college students were surveyed, 145 said they have a passport.  Construct a 95%…

A: Zcrit = 1.96

Q: In a survey of 2033 adults in a recent​ year, 735 made a New​ Year's resolution to eat healthier.…

A: First find out the true population proportion .    Total number of adults in a survey = n= 2033…

Q: In the United States, 1000 residents aged 15 or older were surveyed and 870 replied that they were…

A:

Q: Out of 600 people sampled, 42 had kids. Based on this, construct a 99% confidence interval for the…

A: Given;n = 600x = 42confidence level 99%

Q: In a survey of 356 people who attended a local professional soccer teams most recent home game, 135…

A:

Q: In a sample of 190 adults, 133 had children. Construct a 90% confidence interval for the true…

A: Given:n = 190x = 133Confidence level = 90%

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.