立In a survey of 2480 golfers, 15% said they were left-handed. The survey's margin of error was 3%. Construct a confidence interval for the proportion of left-handed golfers.O A. (0.11,0.19)O B. (0.18,0.21)OC. (0.12,0.15)O D. (0.12,0.18)Type here to search1320,LockPgUpHomeEnter

We want to find the CI for population proportion (p)

Answered: In a survey of 2480 golfers, 15% said…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A survey asked, "How many tattoos do you currently have on your body?" Of the 1203 males surveyed, 184 responded that they had at least one tattoo. Of the 1067 females surveyed, 133 responded that they had at least one tattoo. Construct a 99% confidence interval to judge whether the prope one tattoo differs significantly from the proportion of females that have at least one tattoo. Interpret the interval. Let p, represent the proportion of males with tattoos and p, represent the proportion of females with tattoos. Find the 99% confidence interval for p, - P2- The lower bound is The upper bound is (Round to three decimal places as needed.)
In a survey of 2275 adults, 709 say they believe in UFOS. Construct a 90% confidence interval for the population proportion of adults who believe in UFOS. A 90% confidence interval for the population proportion is ( ). (Round to three decimal places as needed.)
Three hundred randomly selected people were asked a Yes or No question. The resulting 95% confidence interval for the proportion of Yes responses in the population is(.201, .299). How many people in the sample of 300 responded Yes? ______
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
If [0.64, 0.82] is a confidence interval for the population proportion. Find the value of the point estimator of the population proportion. Select one: O a. 0.73 O b. 0.70 O c. 0.74 O d. 0.72
Construct the confidence interval for the population mean u .c=.98, x=6.4, o=0.7, n = 40
A survey asked, "How many tattoos do you currently have on your body?" Of the 1233 males surveyed, 183 responded that they had at least one tattoo. Of the 1042 females surveyed, 139 responded that they had at least one tattoo. Construct a 95% confidence interval to judge whether the proportion of males that have at least one tattoo differs significantly from the proportion of females that have at least one tattoo. Interpret the interval. C Let p₁ represent the proportion of males with tattoos and p2 represent the proportion of females with tattoos. Find the 95% confidence interval for p₁ -P2- The lower bound is The upper bound is (Round to three decimal places as needed.)
In a survey of 2300 adults, 718 say they believe in UFOS. Construct a 90% confidence interval for the population proportion of adults who believe in UFOS. A 90% confidence interval for the population proportion is (,). (Round to three decimal places as needed.)
A 95% confidence interval for a population proportion, p, is 0.23 < p < 0.27. What was the sample proportion?
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 29. (Round your answer to three decimal places.)
In a sample of 100 college students, 25 of them own a car. Calculate the 95% confidence interval for the true population of college students who own a car. Choose the closest one. A. (0.165132, 0.334868) B. (0.231725, 0.452302) C. (0.25, 0.75) D. (0.1, 0.9)

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In a survey of 2480 golfers, 15% said they were left-handed. The survey's margin of error was 3%. Construct a confidence interval for the proportion of left-handed golfers. O A. (0.11,0.19) OB. (0.18,0.21) OC. (0.12,0.15) O D. (0.12,0.18)