In a survey of 1398 people, 987 people said they voted in a recent presidential election. Voting records show that 68% of eligible voters actually did vote. Given that 68% of eligible voters actually did vote, (a) find the probability that among 1398 randomly selected voters, at least 987 actually did vote. (b) What do the results from part (a) suggest? (a) P(X2987)= (Round to four decimal places as needed.) (b) What does the result from part (a) suggest? OA. People are being honest because the probability of P(x2987) is less than 5%. OB. Some people are being less than honest because P(x2987) is at least 1%. OC. Some people are being less than honest because P(x ≥ 987) is less than 5%. OD. People are being honest because the probability of P(x2 987) is at least 1%.
In a survey of 1398 people, 987 people said they voted in a recent presidential election. Voting records show that 68% of eligible voters actually did vote. Given that 68% of eligible voters actually did vote, (a) find the probability that among 1398 randomly selected voters, at least 987 actually did vote. (b) What do the results from part (a) suggest? (a) P(X2987)= (Round to four decimal places as needed.) (b) What does the result from part (a) suggest? OA. People are being honest because the probability of P(x2987) is less than 5%. OB. Some people are being less than honest because P(x2987) is at least 1%. OC. Some people are being less than honest because P(x ≥ 987) is less than 5%. OD. People are being honest because the probability of P(x2 987) is at least 1%.
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
Transcribed Image Text:K
In a survey of 1398 people, 987 people said they voted in a recent presidential election. Voting records show that 68% of eligible voters actually did vote. Given that 68% of eligible voters actually did
vote, (a) find the probability that among 1398 randomly selected voters, at least 987 actually did vote. (b) What do the results from part (a) suggest?
(a) P(X2 987)= (Round to four decimal places as needed.)
(b) What does the result from part (a) suggest?
OA. People are being honest because the probability of P(x ≥ 987) is less than 5%.
OB. Some people are being less than honest because P(x2987) is at least 1%.
OC. Some people are being less than honest because P(x ≥ 987) is less than 5%.
OD. People are being honest because the probability of P(x ≥ 987) is at least 1%.
C
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Step 1
Answer:
From the given data,
sample size (n) = 1398
number of People voted = x = 987
Population proportion (P) = 68% = 0.68
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