in a survey, 13 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $47 and standard deviation of $20. The best point estimate for μμ is . The margin of error for a 95% confidence interval is

Q: A random sample of  46  four-year-olds attending day care centers provided a yearly tuition average…

A: Solution

Q: ou are interested in estimating the the mean weight of the local adult population of female…

A: Population standard deviation is 28. The z-critical value for 97% confidence interval is 2.170 using…

Q: You measure 49 backpacks' weights, and find they have a mean weight of 63 ounces. Assume the…

A: Given,sample size(n)=49sample mean(x¯)=63population standard deviation…

Q: After surgery, patients remain in the hospital for a few days to be recover. Historical data from a…

A: Given,sample size(n)=50sample mean(x¯)=6.2sample standard deviation(s)=7.4

Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

Q: magine that you want to estimate the average home value in your neighborhood.   The standard…

A: standard deviation  σ = $100,000.the maximum margin of error E=$45,000.

Q: The quality control manager at a light bulb factory needs to estimate the mean life of a large…

A: Given data Sample size(n) = 49 Sample mean x̅  = 370 hours Population standard deviation = 77…

Q: Estimate the proportion of steaks that weigh less than 1.3 pounds. e proportion of steaks that weigh…

A:

Q: A sample of the reading scores of 30 fifth graders has mean of 62.the standard deviation of the…

A: Given,   Sample size = 30 Sample mean = 62 Population standard deviation = 15   The objective is to…

Q: The half-life of the active substance in a particular drug was measured in 15 subjects. The mean…

A: sample size ( n) = 15 sample mean (X̅) = 4.55 sample standard deviation (s) = 1.23

Q: you want to obtain a sample to estimate a population mean. based on previous evidence, you believe…

A:

Q: The population distribution is normally distributed and has a mean of 13.6 and a standard deviation…

A: Normal distribution is a continuous distribution which has many real life applications. Normal curve…

Q: SAT scores are distributed with a mean of 1,500 and a standard deviation of 300. You are interested…

A:

Q: You want to obtain a sample to estimate a population mean age. Based on previous evidence, you…

A: Given data,σ=2.2E=0.75z-value at 95% confidence is Zc=1.96n=?

Q: Annual salary plus bonus data for chief executive officers are presented in an annual pay survey. A…

A: The formula for the sample size is as follows:

Q: You collect a random sample of 50 children and compute X¯X¯, the average height in inches. The…

A: Given that, x¯=50,s=10,n=50 The degree of freedom is, df=n-1   =50-1   =49 Critical value: Using the…

Q: An electric cooperative needs to know the main household usage of electricity but it’s…

A: GivenMargin of error(E)=0.12standard deviation(σ)=2confidence level=85%

Q: You are interested in estimating the the mean weight of the local adult population of female…

A: Given that the population standard deviation is 17 pounds. Confidence level is 96% Margin of error…

Q: You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe…

A: Population Standard deviation = 58.5Confidence interval = 99%Significance level(α) = 1- 0.99 =…

Q: FIND THE test statistics value  FOR  TWO TAILED TEST  SAMPLe sixe 26 and level of significance is…

A:

Q: A hospital would like to determine the mean length of stay for its patients having abdominal…

A: From the provided information, Sample size (n) = 23 Sample mean (x̄) = 5.2 Sample standard deviation…

Q: You wish to estimate the current mean birth weight of all newborns in a certain region, to within 1…

A: Given : Margin of error, E = 116 =0.0625 pound confidence level = 95% α = 0.05 zα2 = z0.052 zα2 =…

Q: You are interested in estimating the the mean weight of the local adult population of female…

A: Determine the sample size n needed. Here, confidence level is 0.96. Use EXCEL Procedure for…

Q: You measure 46 backpacks' weights, and find they have a mean weight of 36 ounces. Assume the…

A:

Q: You are interested in estimating the the mean weight of the local adult population of female…

A:

Q: You are interested in estimating the the mean weight of the local adult population of female…

A:

Q: A study of 77 golfers showed that their average score on a particular course was 93. The st.dev. of…

A: 1). Assume, μ  be the population mean golfers score. x be the random variable representing the…

Q: part 3 question 1 A survey of 35 adults found that the mean age of a person's primary vehicle is…

A: 95% confidence level α=1-0.95   =0.05zα2=1.96

Q: AT scores are distributed with a mean of 1,500 and a standard deviation of 300. You are interested…

A: It is given that:

Q: The net weight in pounds of a packaged chemical herbicide is uniform for 49.75 < x < 50.25 pounds.…

A: From the information, given thatLet X denotes the net weight of a packaged chemical herbicide in…

Q: You are interested in estimating the the mean weight of the local adult population of female…

A: Standard deviation(σ) = 29Margin of error (E) = 8Significance level (α) = 1 - 0.96 = 0.04

Q: Part 1 of 3  A researcher was investigating the size of math departments in Texas colleges. She…

A: Part 1: Suppose that µ is the population mean size of math departments in Texas colleges.

Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.