130.222 and 0.324 are incorrect In a study of the accuracy of fast food drive-through orders, Restaurant A had 209 accurate orders and 57 that were not accurate.a. Construct a 90% confidence interval estimate of the percentage of orders that are not accurate.b. Compare the results from part (a) to this 90% confidence interval for the percentage of orders that are not accurate at Restaurant B: \(0.195 < p < 0.274\). What do you conclude?---a. Construct a 90% confidence interval. Express the percentages in decimal form.\[0.222 < p < 0.324\] (Round to three decimal places as needed.)

Given: Number of accurate orders, X1=209 Number of inaccurate orders, X2=57 We need to construct 90% confidence interval estimate of the percentage of orders that were not accurate.Total orders are given by; n=n1+n2=209+57=266 The sample proportion of orders that were not accurate is given by; p^=X2n=57266=0.214285714≅0.2143 Confidence level=90% Level of significance is given by; (1-α)=0.90α=1-0.90α=0.10 The critical value of the statistic is given by; zc=zα2=z0.102=1.644854≅1.645 The above critical value is calculated using the Excel function ABS(NORMSINV(0.10/2)) as shown in the snip below.a) 90% confidence interval estimate of the percentage of orders that were not accurate is given by; CI=p^±zc p^×(1-p^)n=0.2143±1.64 0.2143×(1-0.2143)266=0.2143±0.0413=(0.1730,0.2555) Therefore, 90% confidence interval estimate of the percentage of orders that were not accurate is (0.1730,0.2555).b) 90% confidence interval estimate of the percentage of orders that were not accurate in Restaurant A is (0.1730,0.2555). 90% confidence interval estimate of the percentage of orders that were not accurate in Restaurant B is (0.195,0.274). We see that , the 90% confidence interval estimate of the percentage of orders that were not accurate in Restaurant A is wider than the confidence interval for Restaurant B. We conclude that we are 90% confident that the true proportion value of percentage of orders that were not accurate in Restaurant A lies in the range (0.1730,0.2555).