In a study of an automobile insurance a random sample of 80 body repair costs had a mean of 472.36 and a standard deviation of 62.35. If x is used as a point estimate to the true average repair costs, with what confidence we can assert that the maximum error doesn't exceed 710?
Q: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
A:
Q: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
A: mu = 3.7 n = 91 s = 1.2 xbar = 6.1
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A: Babies born after a gestation period of 32 to 35 weeks have a mean weight of 2600 grams and a…
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A: Given information: μ=600 mmx¯=596 mms=3 mmn=15
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A: Solution: From the given information, confidence level is 0.94, σ=25 and E=12.
Q: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
A: Null Hypothesis (H0) : μ ≤ 3.7 Alternate Hypothesis (Ha) : μ > 3.7 Given, mean (xbar) = 6.1 σ =…
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A: Given Data : Population Mean,μ = 400 Population Standard Deviation,σ = 20
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A: Null hypothesis: H0: μ = 141. Alternative hypothesis: H1: μ ≠141. Here, the sample mean, x-bar is…
Q: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
A: The objective is to check whether the level for a medication used to treat arthritis is higher than…
Q: Suppose babies born after a gestation period of 32 to 35 weeks have a mean weight of 2600 grams and…
A: We have given thatfor 32 to 35 weeks Mean()= 2600standard deviation() =600andfor 40 weeks mean()=…
Q: Suppose babies bom after a gestation period of 32 to 35 weeks have a mean weight of 2700 grams and a…
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Q: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
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Q: A psychologist is studying smokers' self-images, which she measures by the self-image (SI) score…
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Q: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
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Q: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
A: The hypotheses for the test are given below. Null hypothesis: H0: µ = 3.7 Alternative hypothesis:…
Q: (a) State the null hypothesis Ho and the alternative hypothesis ₁. Ho H₁:0 (b) Determine the type of…
A: given data μ > 1825n = 80x¯ = 1830σ = 60α = 0.05
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Q: The breaking strengths of cables produced by a certain manufacturer have historically had a mean of…
A: As per our guidelines we are supposed to answer only 3 sub-parts of any question so I am solving…
Q: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
A: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
Q: A psychologist is studying smokers' self-images, which she measures by the self-image (SI) score…
A: The level of significance is 0.05.
Q: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
A: GivenMean(x)=6.1standard deviation(s)=1.2sample size(n)=93level of significance=1%
Q: researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
A: given data, n=93X¯=6.1Stanadard deviation =2.4claim:μ>3.7hypothesis:H0:μ=3.7H1:μ>3.7
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Q: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
A: A researcher studies the mean trough level for a medication used to treat arthritis. The previous…
Q: A researcher suspects the mean trough (the lowest dosage of medication required to see clinical…
A: Given; n=93x¯=6.1σ=2.4 Null and alternative hypothesis for this data is given as-…
Q: what should the researcher’s decision rule look like? Reject H0 if z is less than or equal to…
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Q: Suppose babies bom after a gestation period of 32 to 35 weeks have a mean weight of 2800 grams and a…
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Q: Suppose babies born after a gestation period of 32 to 35 weeks have a mean weight of 2800 grams and…
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- A laboratory claims that the mean sodium level, u, of a healthy adult is 143 mEq per liter of blood. To test this claim, a random sample of 50 adult patients is evaluated. The mean sodium level for the sample is 140 mEq per liter of blood. It is known that the population standard deviation of adult sodium levels is 10 mEq. Can we conclude, at the 0.1 level of significance, that the population mean adult sodium level differs from that claimed by the laboratory? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.)A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 2.4 micrograms/mL, for a level of significance of 1%, what should the researcher’s decision rule look like?A nurse is interested in the amount of time patients spend exercising per day. According to a recent study, the daily workout time per adult follows an approximately normal distribution with a mean of 94 minutes and a standard deviation of 27minutes. If the nurse randomly samples patients in her office to analyze their exercise time and gets a standard error of 3minutes, how many patients did she sample?
- The breaking strengths of cables produced by a certain manufacturer have historically had a mean of 1800 pounds and a standard deviation of 90 pounds. The company believes that, due to an improvement in the manufacturing process, the mean breaking strength, μ, of the cables is now greater than 1800 pounds. To see if this is the case, 100 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1818 pounds. Can we support, at the 0.05 level of significance, the claim that the population mean breaking strength of the newly- manufactured cables is greater than 1800 pounds? Assume that the population standard deviation has not changed. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis Ho and the alternative hypothesis H₁. H :O 1 (b) Determine the…A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 2.4 micrograms/mL, for a level of significance of 1%, what should the researcher’s decision rule look like? Reject H0 if z is less than or equal to –2.326. Reject H0 if z is greater than or equal to 2.326. Reject H0 if z is less than or equal to –2.576. Reject H0 if z is greater than or equal to 2.5760A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 1.2 micrograms/mL, the researcher’s hypothesis, for a level of significance of 1%, should resemble which of the following sets of hypothesis? H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .01 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .01 H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .99 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .99
- A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 1.2 micrograms/mL, the researcher’s hypothesis, for a level of significance of 1%, should resemble which of the following sets of hypothesis? H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .01 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .01 H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .99 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .99In a study of an automobile insurance a random sample of 80 body repair costs had a mean of 2472.36 and a standard deviation of 62.35. If x is used as a point estimate to the true average repair costs, with what confidence we can assert that the maximum error doesn't exceed 10?A researcher claims that the average life span of mice can be extended when the calories in their diet are reduced by approximately 40% from the time they are weaned. The restricted diets are enriched to normal levels by vitamins and protein. Suppose that a sample of 10 mice is fed a normal diet and has anaverage life span of 32.1 months with a standard deviation of 3.2 months, while a sample of 15 mice is fed the restricted diet and has an average life span of 37.6 months with a standard deviation of 2.8 months. Assume the distributions of life spans for the regular and restricted diets are approximately normal withequal variance.(a) State the appropriate hypotheses to test the researcher’s claim.(b) Conduct the test at the 0.05 level of significance. What do you conclude?
- An Internet provider has analyzed the amount of time it’s customers are online per session. It found that the distribution of connect times has a mean a 43 minutes and a standard deviation of 10 minutes. For this distribution find the raw score that corresponds to a z score of 1.1 a researcher suspects the mean trough ( the lowest dosage of medication required to see clincial impprovement of symptoms) level for a medication to treat arthritis is higher than was previously reported in other sutdies. if previous studies found the mean trough level of the population to be 3 micrograms/ml. and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 microgran with a standard deviation of 2.4 micrograms/ml, calculate the z value for the test statistic.During the busy season, it is important for the shipping manager at ShipMundo to be able to estimate the time it takes the loading crew to load a truck. The shipping manager has found that she can model the load times using a normal distribution with a mean of 152 minutes and a standard deviation of 15 minutes. Use this table or the ALEKS calculator to find the percentage of load times between 116 minutes and 149 minutes according to the model. For your intermediate computations, use four or more decimal places. Give your final answer to two decimal places (for example 98.23%).