In a study of 420,137 cell phone users, 142 subjects developed cancer of the brain or nervous system. Test the claim of a somewhat common belief that such cancers are affected by cell phone use. That is, test the claim that cell phone users develop cancer of the brain or nervous system at a rate that is different from the rate of 0.0340% for people who do not use cell phones. Because this issue has such great importance, use a 0.001 significance level. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. O B. Ho: p=0.00034 O A. Ho: p<0.00034 H:p= 0.00034 H:p#0.00034 OC. Ho: p= 0.00034 O D. Ho: p#0.00034 H1: p>0.00034 H;: p=0.00034 O E. Ho: p>0.00034 OF. Ho: p=0.00034 H1:p=0.00034 H;:p<0.00034 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion on the null hypothesis? O A. Reject the null hypothesis because the P-value is greater than the significance level, a. O B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. O C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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In a study of 420,137 cell phone users, 142 subjects developed cancer of the brain or nervous system. Test the claim of a somewhat common belief that such cancers are affected by cell phone use. That is, test the claim that cell phone users develop cancer of the brain or nervous system at a rate that is different from the rate of 0.0340% for people who do not use cell phones. Because this issue has such great importance, use a 0.001 significance level. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.

Options provided for hypotheses:

A. \( H_0: p < 0.00034 \)
\( H_1: p = 0.00034 \)

B. \( H_0: p = 0.00034 \)
\( H_1: p \neq 0.00034 \)

C. \( H_0: p = 0.00034 \)
\( H_1: p > 0.00034 \)

D. \( H_0: p \neq 0.00034 \)
\( H_1: p = 0.00034 \)

E. \( H_0: p > 0.00034 \)
\( H_1: p = 0.00034 \)

F. \( H_0: p = 0.00034 \)
\( H_1: p < 0.00034 \)

**Questions:**

1. What is the test statistic?

   \( z = \) [   ] (Round to two decimal places as needed.)

2. What is the P-value?

   P-value = [   ] (Round to four decimal places as needed.)

3. What is the conclusion on the null hypothesis?

   - A. Reject the null hypothesis because the P-value is greater than the significance level, \( \alpha \).
   - B. Fail to reject the null hypothesis because the P-value is greater than the significance level, \( \alpha \).
   - C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, \( \alpha \).

Please note that this text analysis requires statistical computations to determine the correct test statistic, P-value, and
Transcribed Image Text:In a study of 420,137 cell phone users, 142 subjects developed cancer of the brain or nervous system. Test the claim of a somewhat common belief that such cancers are affected by cell phone use. That is, test the claim that cell phone users develop cancer of the brain or nervous system at a rate that is different from the rate of 0.0340% for people who do not use cell phones. Because this issue has such great importance, use a 0.001 significance level. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. Options provided for hypotheses: A. \( H_0: p < 0.00034 \) \( H_1: p = 0.00034 \) B. \( H_0: p = 0.00034 \) \( H_1: p \neq 0.00034 \) C. \( H_0: p = 0.00034 \) \( H_1: p > 0.00034 \) D. \( H_0: p \neq 0.00034 \) \( H_1: p = 0.00034 \) E. \( H_0: p > 0.00034 \) \( H_1: p = 0.00034 \) F. \( H_0: p = 0.00034 \) \( H_1: p < 0.00034 \) **Questions:** 1. What is the test statistic? \( z = \) [ ] (Round to two decimal places as needed.) 2. What is the P-value? P-value = [ ] (Round to four decimal places as needed.) 3. What is the conclusion on the null hypothesis? - A. Reject the null hypothesis because the P-value is greater than the significance level, \( \alpha \). - B. Fail to reject the null hypothesis because the P-value is greater than the significance level, \( \alpha \). - C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, \( \alpha \). Please note that this text analysis requires statistical computations to determine the correct test statistic, P-value, and
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