In a study conducted by some Statistics students, 71 people were randomly assigned to listen to rap music, music by Mozart, or no music while attempting to memorize objects pictured on a page. They were then asked to list all the objects they could remember. The summary statistics for each group are shown in the table. Complete parts a and b. Rap Mozart No Music Count Mean SD 31 11.61 23 17 8.04 13.92 4.48 3.32 4.84 Let group M correspond to Mozart listeners and group R correspond to rap listeners. Write the null and altenative hypotheses. Choose the correct answer below. OA H Pu- PR=0 Ho: Hw HR =0 H HM HR <0 OC. H Pu- PR<0 D. H Hu- HR=0 Test the hypothesis. t= -3.36 (Round to two decimal places as needed.) P= 0.9993 (Round to four decimal places as needed.) State your conclusion. Use a = 0.05. Do not reject Ho There is no evidence that the mean number of objects remembered by those who listen to Mozart is higher than the mean number of objects remembered by those who listen to rap music. b) Now compare the group that listened to Mozart with the group that listened to no music. Create a 90% confidence interval for the mean difference in memory score between students who listen to Mozart and those who listen Interpret your interval. The 90% confidence interval for the negative difference in means is ). (Round to three decimal places as needed.)

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Solve part B
In a study conducted by some Statistics students, 71 people were randomly assigned to listen to rap music, music by Mozart, or no music
while attempting to memorize objects pictured on a page. They were then asked to list all the objects they could remember. The summary
statistics for each group are shown in the table. Complete parts a and b.
Rap
23
Mozart
No Music
Count
Mean
SD
31
17
11.61
8.04
13.92
4.84
4.48
3.32
Let group M correspond to Mozart listeners and group R correspond to rap listeners. Write the null and alternative hypotheses. Choose the correct answer below.
O A Ho Hu - He =0
HA: HM- HR#0
B. Ho: HM-HR =0
HA HM HR <0
D. H HM- HR =0
HA HM - HR >0
OC. Ho Hu- HR <O
H PM- HR = 0
Test the hypothesis.
t= - 3.36 (Round to two decimal places as needed.)
P= 0.9993 (Round to four decimal places as needed.)
State your conclusion. Use a = 0.05.
Do not reject Ho. There is no evidence that the mean number of objects remembered by those who listen to Mozart is higher than the mean number of objects remembered by those who listen to rap music.
b) Now compare the group that listened to Mozart with the group that listened to no music. Create a 90% confidence interval for the mean difference in memory score between students who listen to Mozart and those who listen to no mu
Interpret your interval.
The 90% confidence interval for the negative difference in means is ( ).
(Round to three decimal places as needed.)
Transcribed Image Text:In a study conducted by some Statistics students, 71 people were randomly assigned to listen to rap music, music by Mozart, or no music while attempting to memorize objects pictured on a page. They were then asked to list all the objects they could remember. The summary statistics for each group are shown in the table. Complete parts a and b. Rap 23 Mozart No Music Count Mean SD 31 17 11.61 8.04 13.92 4.84 4.48 3.32 Let group M correspond to Mozart listeners and group R correspond to rap listeners. Write the null and alternative hypotheses. Choose the correct answer below. O A Ho Hu - He =0 HA: HM- HR#0 B. Ho: HM-HR =0 HA HM HR <0 D. H HM- HR =0 HA HM - HR >0 OC. Ho Hu- HR <O H PM- HR = 0 Test the hypothesis. t= - 3.36 (Round to two decimal places as needed.) P= 0.9993 (Round to four decimal places as needed.) State your conclusion. Use a = 0.05. Do not reject Ho. There is no evidence that the mean number of objects remembered by those who listen to Mozart is higher than the mean number of objects remembered by those who listen to rap music. b) Now compare the group that listened to Mozart with the group that listened to no music. Create a 90% confidence interval for the mean difference in memory score between students who listen to Mozart and those who listen to no mu Interpret your interval. The 90% confidence interval for the negative difference in means is ( ). (Round to three decimal places as needed.)
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