In a steam power plant, the condenser pressure is 10 kPa. The turbine and pump isentropic efficiencies are both 85 %. Draw the schematic and T-S diagrams. Label the points by setting point 1 at the condenser outlet, point 2 at the pump outlet, point 3 at the boiler outlet, and point 4 at the turbine outlet. Use the label 2a and 4a for the points due to the isentropic efficiency of the pump and turbine, respectively. Use 2 decimal places for the enthalpy and other energies in solving and for the final answers. For the steam quality (x) and entropy (s), use 4 decimal places in solving. For the specific volume, use 6 decimal places. The pressure and the temperature of steam that enters the turbine are 4 MPa and 700 oC (use the given values assigned on your name in the table below) Determine the following: Enthalpy at point 1 in kJ/kg= Enthalpy at point 2 in kJ/kg = Enthalpy at point 3 in kJ/kg = Enthalpy at point 4 in kJ/kg = Actual Enthalpy at point 2a in kJ/kg= Actual Enthalpy at point 4a in kJ/kg= Actual Work of pump in kJ/kg= Actual Work of turbine in kJ/kg= Actual Heat added in kJ/kg= Actual Heat rejected in kJ/kg = Actual Net Work in kJ/kg = Actual Thermal Efficiency in %=
In a steam power plant, the condenser pressure is 10 kPa. The turbine and pump isentropic efficiencies are both 85 %. Draw the schematic and T-S diagrams. Label the points by setting point 1 at the condenser outlet, point 2 at the pump outlet, point 3 at the boiler outlet, and point 4 at the turbine outlet. Use the label 2a and 4a for the points due to the isentropic efficiency of the pump and turbine, respectively. Use 2 decimal places for the enthalpy and other energies in solving and for the final answers. For the steam quality (x) and entropy (s), use 4 decimal places in solving. For the specific volume, use 6 decimal places.
The pressure and the temperature of steam that enters the turbine are 4 MPa and 700 oC (use the given values assigned on your name in the table below)
Determine the following:
Enthalpy at point 1 in kJ/kg=
Enthalpy at point 2 in kJ/kg =
Enthalpy at point 3 in kJ/kg =
Enthalpy at point 4 in kJ/kg =
Actual Enthalpy at point 2a in kJ/kg=
Actual Enthalpy at point 4a in kJ/kg=
Actual Work of pump in kJ/kg=
Actual Work of turbine in kJ/kg=
Actual Heat added in kJ/kg=
Actual Heat rejected in kJ/kg =
Actual Net Work in kJ/kg =
Actual Thermal Efficiency in %=
Trending now
This is a popular solution!
Step by step
Solved in 5 steps with 5 images
