Please exaplain not just give answer In a signal phase, pedestrians are allowed to cross the street walking in the same direction as movements #2 and #6. The distance from one side of the street to the next (length of the crosswalk) is 72 ft. The width of the crosswalk is 9.0 ft. What minimum green time should be set aside for 12 pedestrians (both directions combined) to cross per phase? Use the walking speed of 4.0 ft/s. Round your answer to the next second. Suggest a walk interval, pedestrian clearance interval, and buffer interval.

Length of crosswalk - 72 ft -722= 36 ft Width of the crosswalk (We)= 9 ft Walking speed (∆p)= 4ft/sec The width of the crosswalk is less than 10, therefore Npld = 20 To find- a) Green time b) Walk interval c) Pedestrian clearance time d) Buffer interval The minimum green time is given by - Gp=3.2 + L∆P+0.27×Npld substituting the values in the above equation we have - Gp =17.6 sec =18 sec Therefore, the green time for the pedestrian is 17.6 sec A walk interval of 7 seconds is suggested for the calculated green time as the number of pedestrians is low. A buffer interval of 3 seconds is suggested. As from the table, the pedestrian clearance time is given by - Therefore, according to the question the pedestrian clearance time for 36 ft crosswalk and walking speed of 4 ft/sec is - 10 sec