In a saturated solution of a hypothetical phosphate M3PO4, [PO43]= 3.3 x 10-5 M. Calculate Kp for M3PO4. %3D 5.8 x 10-16 1.0 x 10-16 O 3.2 x 10-17 5.6 x 10-19
In a saturated solution of a hypothetical phosphate M3PO4, [PO43]= 3.3 x 10-5 M. Calculate Kp for M3PO4. %3D 5.8 x 10-16 1.0 x 10-16 O 3.2 x 10-17 5.6 x 10-19
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![In a saturated solution of a hypothetical phosphate M3PO4, [PO43-] = 3.3 x 10-5 M. Calculate Ksp for M3PO4.
5.8 x 10-16
1.0 x 10-16
3.2 x 10-17
5.6 x 10-19
6.3x 10-18](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa8fc0b0b-7e23-4ecc-9f5d-0c499ae4a321%2Fcff7d74d-6d71-45e4-a3f6-2b9f74050d0c%2Fkmlboai_processed.png&w=3840&q=75)
Transcribed Image Text:In a saturated solution of a hypothetical phosphate M3PO4, [PO43-] = 3.3 x 10-5 M. Calculate Ksp for M3PO4.
5.8 x 10-16
1.0 x 10-16
3.2 x 10-17
5.6 x 10-19
6.3x 10-18
![Consider the reaction: Cu2+(aq) + 4NH3(aq) 2 Cu(NH3)4²*(aq) Kf = 1.7x 1013
%3D
What is [Cu2+] remaining in solution after 0.020 mol of CuSO4 is dissolved in 1.00 L of 0.70 M NH3? Assume no change of volume.
O 3.8 x 10-14 M.
1.6 x 10-14 M
1.1 x 10-13 M
8.0 x 10-15 M
5.0 x 10-13 M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa8fc0b0b-7e23-4ecc-9f5d-0c499ae4a321%2Fcff7d74d-6d71-45e4-a3f6-2b9f74050d0c%2Ff5jreo_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the reaction: Cu2+(aq) + 4NH3(aq) 2 Cu(NH3)4²*(aq) Kf = 1.7x 1013
%3D
What is [Cu2+] remaining in solution after 0.020 mol of CuSO4 is dissolved in 1.00 L of 0.70 M NH3? Assume no change of volume.
O 3.8 x 10-14 M.
1.6 x 10-14 M
1.1 x 10-13 M
8.0 x 10-15 M
5.0 x 10-13 M
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