Answered: In a sample of 89 people , 18 had type…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Related questions

Concept explainers

Question

In a sample of 89 people , 18 had type A blood,27 had type B blood ,27 had type AB blood and 17 had type O blood group . If a person is selected from this group ,find the following probability that the selected person is of :

a/ type A blood

b/type B or type O blood

c/ neither type A nor type B blood

Expert Solution

Step 1

Given;

Type A blood group=18

Type B blood group=27

Type AB blood group=27

Type O blood group=17

N=89

a) Probability that the selected person is type A blood group is-

$P (t y p e A) = \frac{Total number of type A}{N} = \frac{18}{89} = 0.2022$

b) Probability that the selected person is type B or type O blood

$P (B \cup O) = P (B) + P (O) + P (B \cap O) Since P (B \cap O) = 0 P (B) = \frac{27}{89} = 0.3033 P (O) = \frac{17}{89} = 0.1910 P (B \cup O) = P (B) + P (O) = 0.3033 + 0.1910 P (B \cup O) = 0.4943$

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.

Similar questions