In a rollercoaster ride a passenger car at the top of the first hill is travelling at 3.5 m/s. The car then descends on rails to the bottom of the slope and then goes up the second hill where the speed is 10 m/s. Find the difference in height between the first and second hill. (Result 4.47m
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
Hi,
I have one more follow-up question regarding a similar problem where I need to find the height:
In a rollercoaster ride a passenger car at the top of the first hill is travelling at 3.5 m/s. The car
then descends on rails to the bottom of the slope and then goes up the second hill where the
speed is 10 m/s. Find the difference in height between the first and second hill. (Result 4.47m)
Attached is the formula I tried to use, however, I get a different result so I am definitely doing something wrong. Online I didn't find a similar problem so I am asking here as a last chance. Can you help?
![mghat m
2
/mitmghy = 1 mvetmghe
-
27
2
tvi+ghe = fuz + ghz
ghat ghetupituz
the the = tuit
यू
= + V ₂² ²
४
FOOD](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa4efc2a5-039b-466f-b774-04edf61d54e8%2Fe1832fdb-9340-41d0-b2f2-c8301910e2ad%2Fkcfjr1l_processed.jpeg&w=3840&q=75)
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Solved in 2 steps with 2 images
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The reason why I used 2g instead than g is that I have to cancel 2 "g" from the left side. Meaning I had to add 1/2g on the right side. Why are you instead adding only 1/g? Sorry, sometimes I get lost in the simple steps.
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