In a recent survey of 655 working Americans ages 25 - 34, the average weekly amount spent on lunch was $45.84with standard deviation $3.07. The weekly amounts are approximately bell-shaped. Answer the question below. (a) Estimate the percentage of amounts that are between $36.63 and $55.05.(Choose one)of the amounts fall between $36.63 and $55.05.Approximately 68%Approximately 75%Approximately 95%Approximately 88.9%Almost all

Answered: Image /qna-images/answer/2e954d9c-f20a-4760-bd0f-70e322b98aea.jpg

In a recent survey of 655 working Americans ages 25 - 34, the average weekly amount spent on lunch was $45.84 with standard deviation $3.07. The weekly amounts are approximately bell-shaped. Answer the question below.

In a recent survey of 655 working Americans ages 25 - 34, the average weekly amount spent on lunch was $45.84 with standard deviation $3.07. The weekly amounts are approximately bell-shaped. Answer the question below.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Electricity bills: According to a government energy agency, the mean monthly household electricity bill in the United States in 2011 was $110.55 . Assume the amounts are normally distributed with standard deviation $24.00 . Use the TI-84 Plus calculator to answer the following. The median of the bill amounts is $ .
In a large sample of customer accounts, a utility company determined that the average number of days between when a bill was sent out and when the payment was made is 19 with a standard deviation of 18 days. Assume the data to be approximately bell-shaped. Approximately 95% of all customer accounts have the average number of days between two values A and B. What is the value of B? Write only a number as your answer.
In the 1992 presidential election, Alaska's 40 election districts averaged 2002 votes per district for President Clinton. The standard deviation was 589. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X N b. Is 2002 a population mean or a sample mean? Select an answer ✓ c. Find the probability that a randomly selected district had fewer than 2058 votes for President Clinton. d. Find the probability that a randomly selected district had between 1998 and 2225 votes for President Clinton. e. Find the third quartile for votes for President Clinton. Round your answer to the nearest whole number.
The standard deviation for actuary salaries is o = $38,590. You collect a simple random sample of n = 147 salaries and find that = $123,239. What is the point estimate for the true mean actuary salary? (Round your answer to the nearest whole dollar.)
Students in the psychology department at General State University consumes an average of 7 sodas per day with a standard deviation of 2.5. the distribution is normal. Explain how you would go about answering the following questions (include your answer to the question in your response): How many sodas would an individual at the 75thpercentile drink per day?
In the 1992 presidential election, Alaska's 40 election districts averaged 1824 votes per district for President Clinton. The standard deviation was 573. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. What is the distribution of X? X ~ N(,)b. Is 1824 a population mean or a sample mean? c. Find the probability that a randomly selected district had fewer than 1872 votes for President Clinton. d. Find the probability that a randomly selected district had between 1842 and 2091 votes for President Clinton. e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.
See photo for question details.
In a recent survey of 621 working Americans ages 25-34, the average weekly amount spent on lunch was $44.61 with a standard deviation $3.03. The weekly amounts are approximately bell-shaped. Estimate the percentage of amounts that were greater than $47.64. Round the answer to one decimal place.
Monthly Home Rent The average monthly rent for a one-bedroom home in San Francisco is $1229. A random sample of 15 one-bedroom homes about 15 miles outside of San Francisco had a mean rent of $1350. The population standard deviation is $250. At a 0.05, can we conclude that the monthly rent outside San Francisco differs from that in the city? Source: New York Times Almanac, a. Solve using the traditional approach. b. Confirm your answer to part a using the P – value approach.
In the 1992 presidential election, Alaska's 40 election districts averaged 1993 votes per district for President Clinton. The standard deviation was 584. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X ~ N( b. Is 1993 a population mean or a sample mean? Select an answer v C. Find the probability that a randomly selected district had fewer than 2053 votes for President Clinton. d. Find the probability that a randomly selected district had between 2074 and 2208 votes for President Clinton. e. Find the 95th percentile for votes for President Clinton. Round your answer to the nearest whole number.
Lunch break: In a recent survey of 655 working American ages 25-34, the average weekly amount spent on lunch was $44.60 with standard deviation $2.81. The weekly amounts are approximately bell-shaped. a. Estimate the percentage of amounts that are between $36.17 and $53.03. b. Estimate the percentage of amounts that are between $41.79 and $47.41. c. Between what two values will approximately 95% of the amounts be?
Lunch break: In a recent survey of 680 working Americans ages 25 - 34 , the average weekly amount spent on lunch as $44.51 with standard deviation $3.06 .The weekly amounts are approximately bell-shaped