In a recent study reported Oct. 29, 2012 on the Flurry Blog, the mean age of tablet users is 34 years. Suppose the standard deviation is 15 years. The sample of size is 50. a. What are the mean and standard deviation for the sum of the ages of tablet users? What is the distribution? b. Find the probability that the sum of the ages is between 1,500 and 1,800 years. c. Find the 80th percentile for the sum of the 50 ages.
In a recent study reported Oct. 29, 2012 on the Flurry Blog, the mean age of tablet users is 34 years. Suppose the standard deviation is 15 years. The sample of size is 50. a. What are the mean and standard deviation for the sum of the ages of tablet users? What is the distribution? b. Find the probability that the sum of the ages is between 1,500 and 1,800 years. c. Find the 80th percentile for the sum of the 50 ages.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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![In a recent study reported Oct. 29, 2012 on the Flurry Blog, the mean age of tablet users is 34 years. Suppose the
standard deviation is 15 years. The sample of size is 50.
a. What are the mean and standard deviation for the sum of the ages of tablet users? What is the distribution?
b. Find the probability that the sum of the ages is between 1,500 and 1,800 years.
c. Find the 80th percentile for the sum of the 50 ages.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F32aa45e4-26b5-4c6a-9ced-5c983c42c44e%2Fba8cc4df-b838-46ab-aba8-0d87981b6a63%2Fue2ht0b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In a recent study reported Oct. 29, 2012 on the Flurry Blog, the mean age of tablet users is 34 years. Suppose the
standard deviation is 15 years. The sample of size is 50.
a. What are the mean and standard deviation for the sum of the ages of tablet users? What is the distribution?
b. Find the probability that the sum of the ages is between 1,500 and 1,800 years.
c. Find the 80th percentile for the sum of the 50 ages.
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