In a recent court case, it was found that during an 11-year period, 851 people were selected for grand jury duty, and 41% of them were from the same ethnicity. Among the people eligible for grand jury duty, 80.7% were of this ethnicity. Use a 0.05 significance level to test the claim that the selection process is biased against allowing this ethnicity to sit on the grand jury. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.---**What is the test statistic?**Z = [ ](Round to two decimal places as needed.)**What is the P-value?**P-value = 0.000(Round to four decimal places as needed.)

The hypotheses for the test are given below. Null hypothesis: H0: p = 0.807

Answered: In a recent court case it was found…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a recent court case it was found that during a period of 11 years 860 people were selected for grand jury duty and 37% of them were from the same ethnicity. Among the people eligible for grand jury duty, 79.3% were of this ethnicity. Use a 0.05 significance level to test the claim that the selection process is biased against allowing this ethnicity to sit on the grand jury. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. Question content area bottom Part 1 Which of the following is the hypothesis test to be conducted? A.Upper H 0 : p not equals 0.793 Upper H 1 : p equals 0.793 H0: p≠0.793 H1: p=0.793 B.Upper H 0 : p equals 0.793 Upper H 1 : p not equals 0.793 H0: p=0.793 H1: p≠0.793 C.Upper H 0 : p equals 0.793 Upper H…
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