In a reaction system, the concentrations of Enzyme-Substrate complex [ES], free enzyme [E] and free substrate [S] are 5mM, 2mM and 45 mM respectively. If the enzyme has 5 identical binding sites for this substrate, then calculate the value of Equilibrium Association constant (Ka). BIU@G == HEE = E ¶ ¶ Σ 5 (10
In a reaction system, the concentrations of Enzyme-Substrate complex [ES], free enzyme [E] and free substrate [S] are 5mM, 2mM and 45 mM respectively. If the enzyme has 5 identical binding sites for this substrate, then calculate the value of Equilibrium Association constant (Ka). BIU@G == HEE = E ¶ ¶ Σ 5 (10
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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![In a reaction system, the concentrations of Enzyme-Substrate complex [ES], free enzyme [E] and free
substrate [S] are 5mM, 2mM and 45 mM respectively. If the enzyme has 5 identical binding sites for this
substrate, then calculate the value of Equilibrium Association constant (Ka).
BIU
EEE](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F282857e5-203b-42e4-ba79-02362f0ba948%2F7d61fe6f-2ea2-4fec-a38f-91c7a37e90c6%2F0ohx2li_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In a reaction system, the concentrations of Enzyme-Substrate complex [ES], free enzyme [E] and free
substrate [S] are 5mM, 2mM and 45 mM respectively. If the enzyme has 5 identical binding sites for this
substrate, then calculate the value of Equilibrium Association constant (Ka).
BIU
EEE
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