Also need 90% interval **Transcription with Explanation**In a random sample of six mobile devices, the mean repair cost was $60.00 and the standard deviation was $13.50. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 90% confidence interval for the population mean. Interpret the results.**The 90% confidence interval for the population mean μ is (__, __).**(Round to two decimal places as needed.)---**Explanation (for Educational Context):**This text is part of a statistical analysis exercise designed to teach students how to calculate a confidence interval using a t-distribution. The exercise provides a scenario involving mobile device repair costs and asks students to apply appropriate statistical methods to estimate the population mean.- **Mean Repair Cost**: $60.00- **Standard Deviation**: $13.50- **Sample Size**: 6- **Confidence Level**: 90%Students are expected to use these values to compute the confidence interval, which involves determining the margin of error using the t-distribution (likely with a t-value lookup for the given confidence level and degrees of freedom). The results will provide a range in which the true mean repair cost for the population is likely to fall with 90% confidence. The final step is to interpret this interval in the context of the data provided.

Given Data: Sample mean (x)=60 Sample standard deviation (sd)=13.5 Margin of error t0.1/2,5 ×…

In a random sample of six mobile devices, the mean repair cost was $60.00 and the standard deviation was $13.50. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 90% confidence interval for the population mean. Interpret the results. The 90% confidence interval for the population mean p is ( . ). (Round to two decimal places as needed.)

In a random sample of six mobile devices, the mean repair cost was $60.00 and the standard deviation was $13.50. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 90% confidence interval for the population mean. Interpret the results. The 90% confidence interval for the population mean p is ( . ). (Round to two decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Equations and inequalities describe the relationship between two mathematical expressions.

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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

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Also need 90% interval

**Transcription with Explanation**

In a random sample of six mobile devices, the mean repair cost was $60.00 and the standard deviation was $13.50. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 90% confidence interval for the population mean. Interpret the results.

**The 90% confidence interval for the population mean μ is (__, __).**

(Round to two decimal places as needed.)

---

**Explanation (for Educational Context):**

This text is part of a statistical analysis exercise designed to teach students how to calculate a confidence interval using a t-distribution. The exercise provides a scenario involving mobile device repair costs and asks students to apply appropriate statistical methods to estimate the population mean.

- **Mean Repair Cost**: $60.00
- **Standard Deviation**: $13.50
- **Sample Size**: 6
- **Confidence Level**: 90%

Students are expected to use these values to compute the confidence interval, which involves determining the margin of error using the t-distribution (likely with a t-value lookup for the given confidence level and degrees of freedom). The results will provide a range in which the true mean repair cost for the population is likely to fall with 90% confidence. The final step is to interpret this interval in the context of the data provided.

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