In a random sample of seven ​people, the mean driving distance to work was 20.2 miles and the standard deviation was 5.8 miles. Assuming the population is normally distributed and using the​ t-distribution, a 99​% confidence interval for the population mean μ is (12.1, 28.3) ​(and the margin of error is 8.1​). Through​ research, it has been found that the population standard deviation of driving distances to work is 4.3. Using the standard normal distribution with the appropriate calculations for a standard deviation that is​ known, find the margin of error and construct a 99​% confidence interval for the population mean μ. Interpret and compare the results.       Question content area bottom Part 1 Identify the margin of error.   enter your response here ▼   square miles miles per hour miles ​(Round to one decimal place as​ needed.) Part 2 Construct a 99​% confidence interval for the population mean.   (enter your response here,enter your response here) ​(Round to one decimal place as​ needed.) Part 3 Interpret the results. Select the correct choice below and fill in the answer box to complete your choice. ​(Type an integer or a decimal. Do not​ round.)   A. With enter your response here​% ​confidence, it can be said that most driving distances to work​ (in miles) in the population are between the​ interval's endpoints.   B. enter your response here​% of all random samples of seven people from the population will have a mean driving distance to work​ (in miles) that is between the​ interval's endpoints.   C. With enter your response here​% ​confidence, it can be said that the population mean driving distance to work ​ (in miles) is between the​ interval's endpoints.   D. It can be said that enter your response here​% of the population has a driving distance to work​ (in miles) that is between the​ interval's endpoints. Part 4 Compare these results to the results that used the​ t-distribution.   The new confidence interval is ▼   narrower than as wide as wider than the confidence interval that used the​ t-distribution and has ▼   the same a greater a lesser center.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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In a random sample of
seven
​people, the mean driving distance to work was
20.2
miles and the standard deviation was
5.8
miles. Assuming the population is normally distributed and using the​ t-distribution, a
99​%
confidence interval for the population mean
μ
is
(12.1, 28.3)
​(and the margin of error is
8.1​).
Through​ research, it has been found that the population standard deviation of driving distances to work is
4.3.
Using the standard normal distribution with the appropriate calculations for a standard deviation that is​ known, find the margin of error and construct a
99​%
confidence interval for the population mean
μ.
Interpret and compare the results.
 
 
 

Question content area bottom

Part 1
Identify the margin of error.
 
enter your response here
 
square miles
miles per hour
miles
​(Round to one decimal place as​ needed.)
Part 2
Construct a
99​%
confidence interval for the population mean.
 
(enter your response here,enter your response here)
​(Round to one decimal place as​ needed.)
Part 3
Interpret the results. Select the correct choice below and fill in the answer box to complete your choice.
​(Type an integer or a decimal. Do not​ round.)
 
A.
With
enter your response here​%
​confidence, it can be said that most driving distances to work​ (in miles) in the population are between the​ interval's endpoints.
 
B.
enter your response here​%
of all random samples of
seven
people from the population will have a mean driving distance to work​ (in miles) that is between the​ interval's endpoints.
 
C.
With
enter your response here​%
​confidence, it can be said that the population mean driving distance to work ​ (in miles) is between the​ interval's endpoints.
 
D.
It can be said that
enter your response here​%
of the population has a driving distance to work​ (in miles) that is between the​ interval's endpoints.
Part 4
Compare these results to the results that used the​ t-distribution.
 
The new confidence interval is
 
narrower than
as wide as
wider than
the confidence interval that used the​ t-distribution and has
 
the same
a greater
a lesser
center.
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