Multiple ChoiceIn a random sample of n = 300 families owning television sets in the city, it is found that x = 210subscribe to Netflix. Find a 95% confidence interval for the actual proportion of families withtelevision sets in this city that subscribe to Netflix.0.6814

Answered: Image /qna-images/answer/8d51235d-2988-4e56-a2bd-8fa8fde251aa.jpg

Answered: * In a random sample of n = 300…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher conducted 12 experiments to investigate the lifespan of a certain bacteria in an acidic solution. The collected data shows that the average lifespan of the bacteria is 184 hours with 10.0 hours standard deviation. Based on data what is 95% confidence interval for the mean lifespan of this bacteria in given conditions?
An auditor takes a random sample of 880880 invoices from the 9510 invoices relating to the activities of a company in 2019. The sample mean value of the sampled invoices was £126 and the sample standard deviation was £58. Find a 99% confidence interval for the mean value of all the invoices for 2019. Round to 3 decimal places The records of the company states that the total income from the 9510 invoices was £1150710. The auditor's sample evidence does not support this stated total. True or false? What is the probability, rounded to 3 decimal places, that the company's income does not exceed the value in the records?
Suppose an insurance company randomly surveyed 633 drivers and found that 601 claimed they always buckled up. Construct a 94% confidence interval for the fraction of all drivers who buckle up. p' = NR dje = Margin of Error: E = We are 94% confident that the fraction of drivers who always buckle up is between and
A simple random sample of 36 8th graders at a large suburban middle school indicated that 84% of them are involved with some type of after school activity. Find the 95% confidence interval that estimates the proportion of them that are involved in an after school activity.
In a survey of 28292829 adults, 14121412 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results.
A random sample of ni = 270 people who live in a city were selected and 99 identified as a "dog person." A random sample of n2 = 108 people who live in a rural area were selected and 51 identified as a "dog person." Find the %3D 98% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < pi – P2 < -
A recent survey of two countries in South America reports on data about foreign-born citizens. Of 500 randomly selected people in Peru, 125 reported as being born in another country; meanwhile, 75 of 800 randonly selected Argentinians reported as being foreign-born. Use this information to create a 95% confidence interval for the true difference in proportions of foreign born citizens between Peru and Argentina.
In a large urban city, it was found that in a sample of 6 months, an average of 28 burglaries occurred each month, with a standard deviation of 4. Construct the 95% confidence interval for the true mean number of burglaries to occur in this city each month.
A study of 420,064 cell phone users found that 136 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0343% for those not using cell phones . Use the sample data to construct 95% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system.
A random sample of 64 students at a university showed an average age of 25 years and a sample standard deviation of 2 years. The 98 % confidence interval for the true average age of all students in the university is * 20.5 to 29.5. O24.4 to 25.6. 23.0 to 27.0. O 20.0 to 30.0.
A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 226 milligrams withs = 17.9 milligrams. Construct a 98% confidence interval for the true mean cholesterol content of all such eggs

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