In a random sample of eleven cell phones, the mean full retail price was $416.00 and the standard deviation was $199.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 99% confidence interval for the population mean u. Interpret the results.

Q: In a random sample of six people, the mean driving distance to work was 24.9 miles and the standard…

A: The sample size: n=6 Sample mean: x¯=24.9 miles Standard deviation: s=7.9 Confidence level: C=0.99…

Q: In a random sample of eight ​people, the mean driving distance to work was 19.3 miles and the…

A: The question is about confidence interval Given : Randomly selected no. of people ( n ) = 8 Sample…

Q: if a sample n = 16, mean = 10.3,standard deviation is 2.6. calculate a 95% confidence interval.

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Q: In a random sample of twelve ​people, the mean driving distance to work was 21.5 miles and the…

A: Solution

Q: The mean rate for cable t.v.from a sample of 80 households was $29 per month with a standard…

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Q: A random sample of 51 four-year-olds attending day care centers provided a yearly tuition average of…

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Q: In a random sample of 15 ​people, the mean driving distance to work was 18.5 miles and the standard…

A:

Q: In a random sample of five ​people, the mean driving distance to work was 19.9 miles and the…

A: Given Sample size, n = 5 Degree of freedom, n-1 = 4 Sample mean, x = 19.9 miles Sample standard…

Q: In a random sample of ten cell phones, the mean full retail price was $ 457.50 and the standard…

A:

Q: random sample of eight ​people, the mean driving distance to work was 23.6 miles and the standard…

A: Given, sample mean (x̄) = 23.6 sample standard deviation (s) = 5.1 sample size (n) = 8

Q: The monthly rents for studio apartments in Abu Dhabi have a mean of AED 3370 and a standard…

A: given data  μ= 3370σ = 680n = 64mean and standard error= ?

Q: In a random sample of ten ​people, the mean driving distance to work was 18.1 miles and the standard…

A:

Q: The mean annual tuition and fees for a sample of 15 private colleges was $41,200 with a standard…

A: Given: n=15x¯=41200s=5300μ=38000α=0.05 The test hypothesis are, H0: μ=38000H1: μ≠38000. This is a…

Q: In a random sample of ten people, the mean driving distance to work was 21.8 miles and the standard…

A: Given,sample size(n)=10mean(x)=21.8standard deviation(σ)=6.4α=1-0.99=0.01α2=0.005degrees of…

Q: An irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other…

A: Given that,x¯=121.60,σ=6.36,n=36 Critical value: By using the z-tables, the critical value at 10%…

Q: A recent survey of 8 social network sites has a mean of 13.1 million visitors for a specific month.…

A: Given that, Mean = 13.1 Standard deviation = 3.1 Sample size = 8

Q: In a random sample of  eight cell​ phones, the mean full retail price was ​$468.50 and the standard…

A: The information provided in the question are as follows :- Sample size (n) = 8 Sample mean (x̄) =…

Q: The ICU Admission dataset includes a variable indicating the age of the patient. Find and interpret…

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Q: In a random sample of twelve cell​ phones, the mean full retail price was ​$566.50 and the standard…

A:

Q: use the​ t-distribution to find the margin of error and construct a 90​% confidence interval for the…

A: Given that  Sample size (n) = 12 Mean full retail price (x¯)= $597 Standard deviation (s) = $168…

Q: A medical researcher surveyed 9 hospitals and found that the standard deviation for the cost for…

A:

Q: In a random sample of ten ​people, the mean driving distance to work was 23.2 miles and the standard…

A: Provided information is ; Sample size(n) =10  Mean(μ) = 23.2 Sample standard deviation(s) = 5.3…

Q: ten cell​ phones, the mean full retail price was ​$406.50 and the standard deviation was ​$174.00.…

A: Given that  Sample size n =10 Sample mean =406.50 Sample standard deviation =174.00

Q: n a random sample of six mobile​ devices, the mean repair cost was $65.00 and the standard deviation…

A:

Q: In a random sample of twelve ​people, the mean driving distance to work was 18.8 miles and the…

A: From the given information we want to construct 90% confidence interval.

Q: In a random sample of seven cell​ phones, the mean full retail price was ​$402.50 and the standard…

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Q: In a random sample of eight cell​ phones, the mean full retail price was ​$431.50 and the standard…

A:

Q: In a random sample of seven cell​ phones, the mean full retail price was ​$474.50 and the standard…

A: given that,sample mean, x =474.5standard deviation, s =189sample size, n =7

Q: In a randoms sample of six people, the mean driving distance to work was 19.7 miles and the standard…

A: Given, sample mean (x̄) = 19.7 sample standard deviation (s) = 6.1 sample size (n) = 6 significance…

Q: Assume that the population has a normal distribution.  A laboratory tested twelve chicken eggs and…

A: It is given that sample mean is 185 and standard deviation is 17.6.

Q: In a population of 100 male fruit flies, the mean abdomen length is 2.0 mm and the standard…

A: Given  μ=2 and σ=0.3 Use standardization as z=x-μσ

Q: Find the 95% confidence interval for the variance and standard deviation for the time it takes a…

A: given data   sample size(n) = 21 sample standard deviation(s)  = 5.2construct 95 % ci for σ2 and σ .…

Q: In a random sample of seven cell​ phones, the mean full retail price was ​$414.50 and the standard…

A: Given that  Sample Mean \bar XXˉ = 414.50414.50 Sample Standard Deviation (s)(s) = 171171…

Q: In a random sample of 5 mobile​ devices, the mean repair cost was ​$60.00 and the standard deviation…

A: Sample size n =5 Sample mean=60 Standard deviation =12

Q: In a random sample of eleven ​people, the mean driving distance to work was 18.1 miles and the…

A: Given information Sample size (n) = 11 Sample mean x̅ = 18.1 miles Standard deviation (s) = 7.6…

Q: In a random sample of ten cell​ phones, the mean full retail price was ​$433.00 and the standard…

A: The question is about confidence interval Given : Randomly selected cell phone ( n ) = 10 Sample…

Q: A reading class can read an mean of 175 words per minute and a population standard deviation of 20…

A:

Q: In a random sample of twelve cell phones, the mean full retail price was $540.00 and the standard…

A: Givensample size (n) =12sample mean(X)=540standard deviation(σ) = 151α = 1-0.90 = 0.10α2=0.05…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.