In a random sample of 85 automobile engine crankshaft bearings, 10 have a surface finish that is rougher than the specifications allow. Therefore, a point estimate of the proportion of bearings in the population that exceeds the roughness specification is p = x/n = 10/85 = 0.12. Compute for a 95% two-sided confidence interval of p? 2.

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In a random sample of 85 automobile engine crankshaft bearings, 10 have a surface
finish that is rougher than the specifications allow. Therefore, a point estimate of the
proportion of bearings in the population that exceeds the roughness specification is'p
= x/n = 10/85 = 0.12. Compute for a 95% two-sided confidence interval of p?
2.
%3D
Transcribed Image Text:In a random sample of 85 automobile engine crankshaft bearings, 10 have a surface finish that is rougher than the specifications allow. Therefore, a point estimate of the proportion of bearings in the population that exceeds the roughness specification is'p = x/n = 10/85 = 0.12. Compute for a 95% two-sided confidence interval of p? 2. %3D
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