**Constructing a Confidence Interval for a Population Proportion**In a random sample of 500 U.S. adults, 60% said that they believe that the U.S. Congress fails to pass laws that benefit the lives of all Americans. Use these sample statistics to construct a 95% confidence interval for the proportion of all U.S. adults who believe that the U.S. Congress fails to pass laws that benefit the lives of all Americans.Give your answers as decimals, rounded to three decimal places.[Textboxes for input]\(\_\_\_\_\_\) < \( p \) < \(\_\_\_\_\_\)

Answered: In a random sample of 500 U.S. adults,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A genetic experiment with peas resulted in one sample of offspring that consisted of 427 green peas and 158 yellow peas. a. Construct a 90% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?
13. A simple random sample of 1100 males aged 12 to 17 in the United States were asked whetherthey played massive multiplayer online role-playing games (MMORPGs); 775 said that they did.We want to use this information to construct a 95% confidence interval to estimate theproportion of all U.S. males aged 12 to 17 who play MMORPGs.Construct a 95% confidence interval to estimate the proportion of 12-to-17 year-old males who play MMORPGs Follow the 4-Step Plan (State, Plan, Do, Conculde)
Suppose that in a recent poll, 550 of the 915 randomly selected U.S. adults agreed with the statement “social media sites like Facebook and Twitter do more to divide the country” (as opposed to unite the country, or neither). a. Use this information to construct a 90% confidence interval.
10
A college administrator is interested in determining the proportion of students who receive some sort of financial aid. Instead of examining the records for all students, the administrator randomly draws 120 students and finds that 48 of them are receiving financial aid. Use a 90% confidence interval to estimate the true proportion of students who receive financial aid.
A political scientist claims that 38% of first-year college students characterize themselves as being “moderate” or “middle of the road” as far as their political affiliation is concerned. Believing this claimed value is too high, you survey a random sample of 400 first-year college students and find that 120 characterize themselves as being “moderate” or “middle of the road.” Based on this information, what will the test statistic be? Choose the answer below that is closest to what you calculate, and try not to do a lot of rounding until you get to the very end of your calculations. 1. -0.3 2. -1.2 3. -2.6 4. -3.3 5. None of the other answer options are correct because the test statistic should be positive, not negative.
Credit card ownership varies across age groups. Suppose that the estimated percentage of people who own at least one credit card is 64% in the 18–24 age group, 84% in the 25–34 age group, 75% in the 35–49 age group, and 77% in the 50+ age group. Suppose these estimates are based on 465 randomly selected people from each age group. (a) Construct a 95% confidence interval for the proportion of people in the 18–24 age group who own at least one credit card. (Round your answers to four decimal places.) to Construct a 95% confidence interval for the proportion of people in the 25–34 age group who own at least one credit card. (Round your answers to four decimal places.) to Construct a 95% confidence interval for the proportion of people in the 35–49 age group who own at least one credit card. (Round your answers to four decimal places.) to Construct a 95% confidence interval for the proportion of people in the 50+ age group who own at least one credit card. (Round your answers to four…
In a study designed to determine whether there was a cluster of brain cancer cases at a Pratt & Whitney plant, record from 223,000 employees were studied and 723 employees with brain tumors were found. Treat those employees as a random sample and construct a 95% confidence interval estimate of the proportion of all adults who develop such tumors. write a brief statement interpreting that confidence interval.
A newspaper infographic titled "Social Media Jeopardizing Your Job?" summarized data from a survey of 1,850 recruiters and human resource professionals. The infographic indicated that 52% of the people surveyed had reconsidered a job candidate based on his or her social media profile. Assume that the sample is representative of the population of recruiters and human resource professionals in the United States. Would a 90% confidence interval be wider or narrower than the 95% confidence interval from part (a)? widernarrower
Construct a 99% confidence interval for the proportion of all motorbike license applications that are misplaced by the department of transport, if a survey found that 20 out of a sample of 175 applications had been misplaced.
In the Star and Tribune newspaper, there is an article entitled "1 in 8 school buses fail tests." The article says that the overall statewide proportion of school buses that fail safety tests is 9%. However, one bus company has a higher rate of over 12%. Assume that we want a new estimate for the statewide proportion of school buses that fail the safety inspection. How large a sample would you have to take in order to construct a 95% confidence interval estimate for the true proportion of buses that fail the inspection and achieve a margin of error of plus or minus 2%? (your answer should be an integer)
An employment agency wants to see which of three types of ads in the help-wanted section of local newspapers is the most effective. Three types of ads (big headlines, straightforward, and bold print) were randomly alternated over a period of weeks, and the number of people responding to the ads was noted each week. Type of Advertisement Big Headline Straightforward Bold Print Number of responses (replicates) 37 23 28 32 30 33 44 31 33 37 26 29 24 27 32 39 40 Do these data support the null hypothesis that there is no difference in the effectiveness of the ads, as measured by the mean number responding, at the .01 level of significance? (a) Find the test statistic. (Give your answer correct to two decimal places.)(b) Find the critical value. (Give your answer correct to two decimal places.)(c) State the appropriate conclusion. Reject the null hypothesis, there is not significant evidence of a difference in effectiveness of the…

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