Can this be done in Java and not C++ In a program, write a method that accepts two arguments: an array of integers and a number n. The method should print all of the numbers in the array that are greater than the number n (in the order that they appear in the array, each on their own line).In the same file, create a main method and call your function using the following data sets:The array {1, 5, 10, 2, 4, -3, 6} and the number 3.The array {10, 12, 15, 24} and the number 12.

We have to write a method that accepts an array of integers and number n as parameters and then print all the numbers in the array which are greater than n. Also, in the main method the function should be called for the data sets: array {1,5,10,2,4,-3,6} and number n=3 array {10,12,15,24} and number n=12.Approach: Create a method that takes the array and number n as parameters. Inside the method traverse the array using a 'for' loop and if the element of the array is greater than the number n then print it in the output. Inside the main method declare the two arrays and call the method. twice by the passing the array and respective value of n. Source Code: public class Main{ //main method to test the code public static void main(String[] args) { int []arr1 = {1,5,10,2,4,-3,6}; int []arr2 = {10,12,15,24}; System.out.println("Dataset 1: "); printGreaterThan_n(arr1, 3); System.out.println("\nDataset 2: "); printGreaterThan_n(arr2,12); } //required method public static void printGreaterThan_n(int []arr, int n){ int size = arr.length; for(int i=0;i<size;i++){ if(arr[i]>n){ System.out.println(arr[i]); } } }}