In a program designed to help patients stop​ smoking, 195 patients were given sustained​ care, and 82.6 % of them were no longer smoking after one month. Among 193 patients given standard​ care, 62.7% were no longer smoking after one month. Construct two 95% (Wald) confidence interval estimates of the percentages of success. Compare the results. What do you​ conclude?

Q: In a Gallup poll of 804 randomly selected adults living in the 50 U.S. states and the District of…

A: Answer x =466n =804Confidence interval =95%

Q: Several years ago, 44% of parents who had children in grades K-12 were satisfied with the quality of…

A: The claim is that 44% of parents who had children in grades K-12 were satisfied with the quality of…

Q: Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given claim: 50% of the parents who had children in grades K-12 were satisfied with the quality of…

Q: When Mendel conducted his famous genetics experiment with peas, one sample of offspring consisted of…

A: Obtain the 95% confidence interval estimate of the percentage of yellow peas. The 95% confidence…

Q: A volunteer wearing a caveman mask was scolded by 158 out of 444 crows he encountered, and the crows…

A: Given information, In a study, a volunteer wear a caveman mask scolded by 158 out of 444 crows he…

Q: Several years ago, 36% of parents who had children in grades K-12 were satisfied with the quality of…

A:

Q: Several years ago, 39% of parents who had children in grades K-12 were satisfied with the quality of…

A: I have used Excel function = NORMSINV() for finding critical value

Q: When you construct a 95% confidence interval, what are you 95% confident about?

A: Confidence intervals: Confidence intervals are the limits for the point estimate of population…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: We surveyed 53 people in an attempt to determine the proportion of Americans who lease a vehicle. 13…

A: The proportion of sample Americans who lease a vehicle is, Thus, the proportion of sample Americans…

Q: adults in a recent​ year, 742 made a New​ Year's resolution to eat healthier.   Construct​ 90% and​…

A: The value of z at a 90% confidence level is 1.645, which can be found by using the standard normal…

Q: In a survey of 2113 adults in a recent​ year, 741 made a New​ Year's resolution to eat healthier.…

A:

Q: Students at Green River plans a study to stats Test scores. Previous research has shown the…

A: We have given that  Margin of error =E =0.5 Population Standard deviation = 1 99%confidence…

Q: Practice. Testing a vaccine for HIV. Of 8198 subjects given a placebo, 74 became infected with HIV,…

A: (a)Given that,sample one, x1 =74, n1 =8198, p1= x1/n1=0.009sample two, x2 =51, n2 =8197, p2=…

Q: Several years ago, 33% of parents who had children in grades K-12 were satisfied with the quality of…

A: The formula for the confidence interval for the proportion is, Here, confidence level is 0.90. Use…

Q: Several years ago, 39% of parents who had children in grades K-12 were satisfied with the quality of…

A: From the provided information, 39% of parents who had children in grades K-12 were satisfied with…

Q: Several years ago, 49% of parents who had children in grades K-12 were satisfied with the quality of…

A:

Q: In a survey, 13 people were asked how much they spent on their child's last birthday gift. The…

A: We have to construct ci.

Q: A survey of 26 individuals found that they spent an average of $39.21 on exercise attire for the…

A: Confidence interval is an inference process which is used to estimate the population parameter. The…

Q: one city, 79.6% of the 8500 students surveyed said they eat at the school cafeteria. Find the 95%…

A: Given n=8500

Q: A telephone poll of 1,000 adult Americans was reported in an issue of a news magazine. One of the…

A: A telephone poll of 1,000 adult Americans was reported in an issue of a news magazine. One of the…

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: Construct a 99% confidence interval to assess whether this represents evidence that parents'…

A:

Q: Several years ago, 42% of parents who had children in grades K-12 were satisfied with the quality of…

A:

Q: A recent survey suggests that 52% of Americans say dogs are their favorite animals. If 84 people are…

A: As per honor code, we will only answer first question: 1)  p=0.52 n=84, p^=0.42 Use the formula of…

Q: Several years ago, 43% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given  Several years ago, 43% of parents who had children in grades K-12 were satisfied with the…

Q: Construct a 95% confidence interval estimate. How does this change your answer to (b)?

A: (d)

Q: An interactive poll found that 397 of 2,391 adults aged 18 or older have at least one tattoo. A.…

A: Given data: Sample size (n) = 2391 x = 397 adults To construct: 1.95 % confidence interval 2.98%…

Q: Several years ago, 44% of parents who had children in grades K-12 were satisfied with the quality of…

A: We have given that 44% of parents who had children in grades K-12 were satisfied with the quality of…

Q: A learn-to-type software program claims that it can improve your typing skills. To test the claim…

A: Before After 52 47 44 42 40 46 50 43 46 34 38 50

Q: A sample of 1,000 employees in an international company was taken to estimate the average…

A: Confidence interval of mean is given by, (X bar + - Z* sigma/√n) Where X bar is mean and sigma is…

Q: A high school counselor is interested in determining factors that contribute to high school drop out…

A: Solution; Given information: n1=41 Sample size of high school  graduatesn2= 38 Sample size of high…

Q: Several years ago, 44% of parents who had children in grades K-12 were satisfied with the quality of…

A: According to the given information in this question We need to find 99% confidence interval

Q: A 95% confidence interval is narrower than a 90% confidence interval for the same data set. O True O…

A: We have to find given probability.

Q: Several years ago, 43% of parents who had children in grades K-12 were satisfied with the quality of…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: Several years  ago, 41 % of parents who had children in grades  K-12 were satisfied with the quality…

A: Given,n=1175x=477p^=xnp^=4771175=0.4061-p^=1-0.406=0.594α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given Data Sample Size, n = 1105 Number of successes, x = 491.0 confidence…

Q: A marketing study by Ford Motor Company finds that 320 of the 650 buyers of compact cars were women.…

A: Let the population proportion of women who bought compact cars be P Given:         Sample size n =…

Q: Several years​ ago, 42​% of parents who had children in grades​ K-12 were satisfied with the quality…

A: Let p be the population proportion of parents satisfied with the quality of education the students…

Q: A psychologist asked a random sample to complete a depression questionnaire. On average, children…

A: The 95% confidence interval for the population mean depression score of children, will signify that,…

Q: Several years ago, 39% of parents who had children in grades K-12 were satisfied with the quality of…

A:

Q: Several years ago, 43% of parents who had children in grades K-12 were satisfied with the quality of…

A:

Q: What is the effect on a confidence interval if one decreases both sample size and the level of…

A:

Q: Several years ago, 46% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given  p=0.46, n=1055, X=488

Q: several years ago, 48% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given that  Sample size n =1035 Favorable cases x =497 Sample proportion p^=x/n  =497/1035 =0.4802

Q: Several years ago, 48% of parents who had children in grades K-12 were satisfied with the quality of…

A: Given : n = 1035 X = 497

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.