In a processing plant, waste heat is to be recovered from a hot oil stream into a cold water stream using a parallel-flow heat exchanger with 0.75 effectiveness. The hot oil enters the heat exchanger at 285 °C with a mass flow rate of 25.0 kg/min while the cold water flows into the heat exchanger at 35 °C with a mass flow rate of 48 kg/min. The specific heat capacities of the oil and the water are 2.2 kl/kg.K and 4.2 ku/kg.K, respectively. The convective heat transfer coefficient on the oil side of the heat exchanger is 58 W/m2.K and that on the water side is 102 w/m².K. Neglect any thermal resistance at the heat transfer wall separating the oil and water streams in the heat exchanger. (a) Calculate the outlet temperatures of the oil and cold water streams in the heat exchanger. (b) Find the number of transfer units (N) of the heat exchanger. (c) Determine the heat transfer area required for the heat exchanger. It is given that for a parallel flow heat exchanger, the effectiveness (e) and the Number of Transfer Units (N) are related by the expression, 1-e-N(1+D) E = [1+ D] where D =- (mc)min (me)max UA N = - (me)min A = heat transfer area, U = overall heat transfer coefficient, m = mass flow rate and c = specific heat capacity.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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In a processing plant, waste heat is to be recovered from a hot oil stream into a cold
water stream using a parallel-flow heat exchanger with 0.75 effectiveness. The hot oil
enters the heat exchanger at 285 °C with a mass flow rate of 25.0 kg/min while the
cold water flows into the heat exchanger at 35 °C with a mass flow rate of 48 kg/min.
The specific heat capacities of the oil and the water are 2.2 kJ/kg.K and 4.2 kl/kg.K,
respectively. The convective heat transfer coefficient on the oil side of the heat
exchanger is 58 W/m?.K and that on the water side is 102 w/m².K. Neglect any
thermal resistance at the heat transfer wall separating the oil and water streams in
the heat exchanger.
(a) Calculate the outlet temperatures of the oil and cold water streams in the heat
exchanger.
(b) Find the number of transfer units (N) of the heat exchanger.
(c) Determine the heat transfer area required for the heat exchanger.
It is given that for a parallel flow heat exchanger, the effectiveness (e) and the
Number of Transfer Units (N) are related by the expression,
1-e-N(1+D)
E = -
[1 + D]
(mc)min
(mc)max
UA
N =
(me)min
A = heat transfer area, U = overall heat transfer
where D =
coefficient, m = mass flow rate andc = specific heat capacity.
Transcribed Image Text:In a processing plant, waste heat is to be recovered from a hot oil stream into a cold water stream using a parallel-flow heat exchanger with 0.75 effectiveness. The hot oil enters the heat exchanger at 285 °C with a mass flow rate of 25.0 kg/min while the cold water flows into the heat exchanger at 35 °C with a mass flow rate of 48 kg/min. The specific heat capacities of the oil and the water are 2.2 kJ/kg.K and 4.2 kl/kg.K, respectively. The convective heat transfer coefficient on the oil side of the heat exchanger is 58 W/m?.K and that on the water side is 102 w/m².K. Neglect any thermal resistance at the heat transfer wall separating the oil and water streams in the heat exchanger. (a) Calculate the outlet temperatures of the oil and cold water streams in the heat exchanger. (b) Find the number of transfer units (N) of the heat exchanger. (c) Determine the heat transfer area required for the heat exchanger. It is given that for a parallel flow heat exchanger, the effectiveness (e) and the Number of Transfer Units (N) are related by the expression, 1-e-N(1+D) E = - [1 + D] (mc)min (mc)max UA N = (me)min A = heat transfer area, U = overall heat transfer where D = coefficient, m = mass flow rate andc = specific heat capacity.
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