Solve the problem.In a population of 210 women, the heights of the women are normally distributed with a mean of 64.4 inches and astandard deviation of 2.9 inches. If 36 women are selected at random, find the mean ux and standard deviation ox ofthe population of sample means. Assume that the sampling is done without replacement and use a finite populationcorrection factor.64.4inches,0.44 inches58.8 inches. 2.65 inches64.4 inches. 2.07 inches64.4 inches. 2.9 inches.

given data population size (N) = 210normal distributionpopulation mean (μ) = 64.4population sd (σ) =…

Answered: In a population of 210 women, the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 100 women are randomly selected, find the probability that they have a mean height greater than 63.0 inches. O A. 0.0082 O B. 0.8989 O C. 0.2881 O D. 0.9918 Next View Instructor Tip Calculator 809 PM 70°F Cloudy 10/8/2021 33 2 Type here to search 10/05/17 PrtSc Insert Delete AI F9 F10 F11 F12 F7 F8 F5 F6 Esc F3 F4 F1 & Backspace Num Lock C@ %23 5 7 080 3 T. Y కాం Home C Tab H. K Enter G A CapsLk 1 Shift C V N End hift PgUp Alt Ctrl End + |/ A MI 小 44
A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 901 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.85 hours with a standard deviation of 0.57 hour. Complete C and D.
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. In a county male height is normally distributed with a mean of 177 cm and astandard deviation of 6 cm. What percentage of males have a height between 170cm and 182 cm.
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