**Title: Confidence Interval for a Population Proportion**In a poll of 175 randomly selected U.S. adults, 94 said they favored a new proposition. Based on this poll, compute a 90% confidence interval for the proportion of all U.S. adults in favor of the proposition (at the time of the poll). Then find the lower limit and upper limit of the 90% confidence interval.Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.)- **Lower limit:** [Input box]- **Upper limit:** [Input box]_Icons and Buttons:_- A button with an 'X' symbol- A button with a circular arrow- A button with a question mark**Note**: This section is designed to guide you through calculating the confidence interval using statistical methods. The input boxes provided will help to record your final answers after performing the necessary calculations.

From the provided information, Sample size (n) = 175 Out of which 94 said they favored a new…

Answered: In a poll of 175 randomly selected U.S.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Let's say you survey a random sample of people. You find that 53% prefer apples over oranges. You make a 90% confidence interval for the proportion of people who prefer apples. The resulting confidence interval is: 0.448 to 0.612 Based on this interval, assess the following statement: We are 90% confident that the proportion of people who prefer apples over oranges is between 0.448 and 0.612 is it : True or False
A political candidate has asked you to conduct a poll to determine what percentage of people support her. If the candidate only wants a 9% margin of error at a 90% confidence level, what size of sample is needed?
In 2001, the polls found that 81% of American adults believed that there was a conspiracy in the death of President Kennedy. Assume a recent poll asked 1500 American adults if they believe there was a conspiracy in the assassination and it found that 1180 believe there was a conspiracy. Calculate a 91% confidence interval for the percentage of all Americans who believe in this conspiracy.
In a survey of 2164 adults in a recent year, 1303 say they have made a New Year's resolution. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. The 90% confidence interval for the population proportion p is (.). (Round to three decimal places as needed.)
Please answer each
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
Suppose that you wanted to know if the percentage of people who will attend a sporting event this year will decrease. Last year, 43% of Americans attended a sporting event. After taking a sample, you attain a sample percentage of 18% with a margin of error of 3%. Construct a confidence interval and use that interval to determine if the number of Americans who will attend a sporting event has decreased. Show your calculation for the interval and then state your conclusion in complete sentences.
You are interested in constructing a 99% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 418 randomly selected caterpillars observed, 59 lived to become butterflies. Round answers to 4 decimal places where possible. a. With 99% confidence the proportion of all caterpillars that lived to become a butterfly is between and . b. If many groups of 418 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion.
In a recent survey of 1264 US adults, 26.6% said they had seen a ghost. What is the LOWER endpoint of a 98% confidence interval for the population proportion? What is the UPPER endpoint of a 98% confidence interval for the population proportion? Answers should be decimals (not percentages).

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